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A) would not be effective

B) sounds like the answer, cause the association probably already did this survey already

C) 10 cats at a local shelter is not very many and too local

D) this would be a good choice, but why would a potential buyer spend money and time to do this?

Logically B is the right answer, but D would be the best if the potenial buyer had all the money and time.

Alright, here we go:

To prove that an expression is never positive, we just need to prove that the maximun value of the expression is smaller than zero.

We can just expand the expression. 

\(3(x+1)(x+7)=3x^2+24x+21\)

\((2x+5)^2=4x^2+20x+25\)

\(3x^2+24x+21- (4x^2+20x+25) = -x^2+4x-4\)

Factoring out the negative one, we have:

\( -(x^2-4x+4)\)

Since

\((x^2-4x+4)\)

is a perfect square, we can rewrite the expression like this:

\(-(x-2)^2\)

Since a square is always positive, and a negative of a square is negative, we proved that the original expression is negative, and always will be negative. 

I hope this answers your question and you have a wonderful day!

Sorry....didn't understand the groupings in your question.....I answered WITHOUT groupings.....

  Melody's answer is correct WITH groupings

6! 4! 5! 3!

= 24883200

I think I can give it a go!

Proof : By the division theorem any number can be expressed in one of the forms 4q,4q+1,4q+2,4q+3

After squaring each of the odd expressions :

\((4q+1)^2= 16q^2+8q+1=8(2q^2+q)+1 \)

\((4q+3)^2=16q^2+24q+9=8(2q^2+3q+1)+1\)

As shown here, it can be expressed as 8 times a number, then added by one. 

I hope this helps!

Fe S  is iron sulfide and has a molar mass  87.91    (Fe 55.845   S 32.06)     100g / (87.91g/mole)  = # moles

1 Mole is 6.022 x 10^23 particles

100 / 87.91   x   6.022 x 10^23 =  number of MOLECULES of FeS

 EACH MOLECULE OF  FeS  has only one ATOM of Fe, so this is the number of Fe atoms.

Since FeS has TWO atoms for each MOLECULE:

The TOTAL number of ATOMS will be double this......     100 / 87.91 x 6.022 x 10^23  x 2  =  # atoms

OK, I will try this: 

You can group the 8 into 3 different groups. And, as groups, you can seat them in:

3! = 6 ways. But the 3 Cubs can be seated in 3! ways, the 3 Red Sox can also be seated in 3! ways, and the 2 Yankees can be seated in 2! ways. So, altogether, they can be seated in:

3! x 3! x 3! x 2! = 432 ways. Somebody should check this.

and pop

I would guess that there would be 314 ways to arrange them.

I have seen this question a while back and that was what I calculated. Nobody answered back so i dont know if it was right.

somebody correct me if im wrong.

This is how you figure that out:

[59 x 58 x 57 x 56 x 55 x ............all the way down to 1] / [54 x 53 x 52 x 51......all the down to 1 x [5 x 4 x 3 x 2 x 1] =[59 x 58 x 57 x 56 x 55] /[5 x 4 x 3 x 2 x 1] =600,766,320 / 120 =5,006,386. Then you would multiply this number by 35 =175,223,510

The first thing you have to do is to convert 6% from compounded semi-annually to compounded monthly. And you can do that as follows:

1.03^(1/6) =1.004938622 - 1 x 100 =0.4938622% - This is the monthly compound rate.

0.4938622 x 12 =5.9263464% - This is the annual rate compounded monthly.

I shall use this amortization schedule to give you all the answers you want:

http://www.calculator.net/amortization-calculator.html?cloanamount=150000&cloanterm=30&cinterestrate=5.9263464&printit=0&x=55&y=25

All the answers to your question are in the above amortization schedule:

Look at the top and you will see the monthly payment = $892.24

Look at the last column of the table where it says "Ending Balance". Go down that column until you see a balance closest to $75,000, and, quickly, you will see that after the 251st payment the balance of the loan will be =$75,064.79, which the closest to $75,000 as you can get.

I hope this answers all your questions. Good luck.

BIngo

David's father has three sons. Snap, Crackle, and _DAVID____?

Option B, I think they would recive the most amount of differing results from the 10 kids.

 Thanks for your help!

59 x 58 x 57 x 56 x 55 = 600766320  Is that what you mean by c5 ?

Your first answer is what I need help with figuring out as it's the correct answer.

How many possible combinations of six Powerball numbers are there, where five white numbers are chosen from 1 through 59 and one red Powerball number is chosen from 1 through 35?

The above odds that you want calculated are obsolete. But even so, the old odds were:

59C5 x 35 =175,223,510 to 1

The new odds are:

69C5 x 26 =292,201,338 to 1

That does not answer my math question! Read the question it says as of 2014.

I'm no expert in Chemistry, but I will give it a shot!
There is no such thing as FeS!, as far as I know.  But, there is
FeSO4, (Iron(II) sulfate or Ferrous sulfate), which has a molecular weight of about 152 g/mol.
The ratio of Fe in FeSO4 =~56 / 152 =0.368421
1 mole of  FeSO4 =6.0221415 x 10^23 atoms. But you have only 100 grams. So 100 / 152 =0.657895 of 1 mole of FeSO4 . So:
0.368421 x 0.657895 x 6.0221415 x 10^23 =1.46 x 10^23 atoms of Fe.

Note: Somebody should check this!.

The rules that you have stated in your question have been changed since 2015 and are no longer used. Read about the new rules and the odds here in Wikipedia:

https://en.wikipedia.org/wiki/Powerball

We have

(x +2) (x - 5) ( x + 6)

[ x^2 + 2x - 5x - 10 ]  [ x + 6 ]

[ x^2 - 3x - 10] [ x + 6 ] 

x [ x^2 - 3x  - 10 ]  +  6 [ x^2 - 3x - 10 ]   

x^3 - 3x^2 - 10 x  + 6x^2 - 18x - 60        combine like terms

x^3 + 3x^2 - 28x - 60

How many integers are there on the number line between

\( \dfrac{17}{3} and \left(\dfrac{17}{3}\right)^2\)

17/3  = 5 + 2/3.....so the next integer is 6

(17/3)^2  = 32 + 1/9....so...the interger before this  is 32

So....the number of integers  between  these two values is

32  - 6  +  1  =    27

60x^2 + 48x + 24

12 ( 5x^2 + 4x + 2)

Where "12"  is the number of ounces in each bottle and the trinomial is the varable number of bottles

I had to cheat on this one a little, ACG....I wasn't sure about how to  construct a square in a semi-circle without a little online "help"....LOL!!!!...oh, well..."any port in a storm "

Look at the following :

Without a loss of generality, let us construct  rectangle ABEF where AB  = 2  and AF  = 4.....the area of this is 8....so by symmetry, the square ABCD has an area of 4.....

Next....draw diagonal BF and construct a circle with G as a center and GB as a radius.....then square  ABCD will be the largest square that we can inscribe  in the upper half of the circle....and it will have an area of AB^2  = 2^2  = 4

Because GC  = (1/2 )AB  = 1   and BC  = AB  = 2, then, by the Pythagorean Theorem,  the radius of the circle, GB, is a hypotenuse of a right triangle and  will be equal to  √[ GC^2 + BC^2]  = √[ 1^2 + 2^2]  = √5

So  we can construct square HIJK  where  H  = (√5/√2, √5/√2)  and  I  = (- √5/√2, √5/√2)

So....HI   will be the side of the square   and its length is  just  √  ( √5/√2 -  -√5/√2)^2  =

(√5/√2 + √5/√2)   =  2√5/√2  = (2/√2)*√5 =   √2*√5  =  √10

So the area of this square  is just  HI^2  = (√10)^2  = 10

So.....since any construction will yield the same ratio....the ratio of the area of a square inscribed in a semicircle with radius r to the area of a square inscribed in a circle with radius r =   4/10   =  2/5

Haha lol. 

Hectictar gave a good answer to  this here :

https://web2.0calc.com/questions/please-help-ty_3#r1

A  = 2*pi*r^2 + 2*pi*r*h     factor out  "pi'

A = pi  [ 2r^2  + 2rh ]      divide both sides by   [ 2r^2 + 2 rh ]

A  /  [ 2r^2 + 2rh ]  =  pi