All Answers 354377 Answers

According to the Law of Cosines,

b²  =  a² + c² - 2ab cos B

                                                          Plug in the given values for  a ,  b , and  c .

12²  =  11² + 17² - 2(11)(17) cos B

                                                          Simplify each side of the equation.

144  =  121 + 289 - 374 cos B

144  =  410 - 374 cos B

                                                          Subtract  410  from both sides of the equation.

144 - 410  =  -374 cos B

-266   =   -374 cos B

                                                          Divide both sides ny  -374 .

-266 / -374   =   cos B

133 / 187   =   cos B

                                                          Take the inverse cosine of both sides.

B  =  arccos(133/187)

                                                          Plug in arccos(133/187) into a calculator to get that...

B   ≈   44.665°

Charchters that did change were Todd, Niel,Chris,Knox.

bruh stop it get some help. Just ask someone

The 1 must go in the upper-left box, and the 6 must go in the lower-right box. There are still two boxes left in the first row. There are four numbers left to choose from, namely 2, 3, 4, and 5. There are six ways to choose two numbers from these four numbers, namely 2 and 3, 2 and 4, 2 and 5, 3 and 4, 3 and 5, and 4 and 5. Once these numbers are chosen, the smaller number must go on the left, and the larger number must go on the right. Then the remaining three numbers must fill the second row, in increasing order. Of all six arrangements, only the arrangement in the lower-right corner does not work (a 4 is above a 3), so there are 5 possible arrangements.

TY Very much 😊😊😀

Thank you ! 

Donut, your answer is not correct!

The mode for the second group is 40 because it appears the most times!

So C is not correct.

Thanks Hectictar  

Take a look at this page Teo    

Just divide:

(3/4) / (7/8) =

(3/4) x (8/7 =

24 / 28       =        divide both sides by 4

6 / 7

0.68=68/100

17/25=68/100

So, no, 0.68 is not greater than 17/25

7/24 - (x + 1)/8<=(x - 3)/6             multiply both sides by 24

7 - 3(x + 1) <= 4(x - 3)

7 - 3x - 3 <= 4x - 12                      add 3x to both sides

7 - 3 <= 7x - 12

4 <= 7x - 12                                   add 12 to both sides

16 <= 7x                                        divide both sides by 7

16/7 <= x, OR:

x >= 16/7

Part A:

rectangle

The base is a rectangle, so a cross section parallel to the base is also a rectangle.

Part B:

triangle

The lateral face of a pyramid is a triangle, so a cross section that passes through the top vertex and the base is also a triangle.

0.68   =   \(\frac{68}{100}\)

\(\frac{17}{25}\)   =   \(\frac{17}{25}\cdot\frac44\)   =   \(\frac{68}{100}\)

\(\frac{68}{100}=\frac{68}{100}\\~\\0.68=\frac{17}{25} \)      so

So no,  0.68  is not greater than  17/25 .

First lets transfer 17/25 to decimal.

We can do that by multiplying 17 and 25 both by 4, giving 68/100

68/100 is equal to .68, so .68 is not greater than 17/25

Donut🍩🍩🍩

The inequality at step 3 is wrong.

\(\big(\frac44\big)\frac{x-3}{6}\)     does not equal     \(\frac{4x-3}{24}\)

\(\big(\frac44\big)\frac{x-3}{6}\)     does equal     \(\frac{4x-12}{24}\)

The student did not correctly distribute the  4  in the numerator.

The second error occurs at step 8. When both sides of an inequality are divided by a negative number, the inequality sign needs to be flipped.

Deleted due to wrong answer given.

slope of Line A   =   [ y₂ - y₁ ] / [ x₂ - x₁ ]

slope of Line A   =   [ -7 - 8 ] / [ 1 - 6 ]

slope of Line A   =   [  -15  ] / [  -5  ]

slope of Line A   =   3

Line A is perpendicular to Line B and Line C is perpendicular to Line B. Since Line A and Line C are both perpendicular to Line B, Line A and Line C must have the same slope.

slope of Line C   =   3

1.) degenerate hyperbola

2.) pair of intersecting lines

We can choose  one of the two students to drive......there are  2 ways to do this

The other four students  can be arranged  in  4!  = 24 ways

So...the total number of arrangements are   2 * 24   =  48 ways

This uses the haversine formula for calculation....

It is outlined, here :

http://www.movable-type.co.uk/scripts/latlong.html

The calculated distance is  10450km

Thanks Again.

Since  OX  meets chord MN at right angles, it bisects MN....so   XN  =  6

And  OY meets chord PQ at right angles, so it bisects PQ.

And since OX  = OY....chords  MH  and PQ are equidistant  from the center of the circle. And chords that are equidistant from the center of a circle have the same length.

So PQ  = 12.....so YQ  =  6

Is this for your own curiosity??!!

(10^2015-1)/9-2015 =

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