All Answers 358195 Answers

Thank you Heureka!

What do the values in the function represent?

1 and 2

You’re a dog, JB? I always thought of you as an orangutan or a gorilla. ...Someone wants to play. 

JB is actually a very good writer. He majored in journalism over 50 years ago, back in the days of Walter Cronkite and Harry Reasoner.

Sorry, idk

1) The function is an exponential GROWTH function.

2)  2.6 - 1 x 100 = 160 - percent rate change of the function.

A senate committee has 5 Republicans and 4 Democrats. In how many ways can the committee members sit in a row of 9 chairs, such that all 4 Democrats sit together?

Source:

A rectangular tile has a thin diagonal line drawn in its design. The longer dimension of the tile is 12 inches. The angle formed by the diagonal and the shorter side of the tile is 72°.

What is the perimeter of the tile?

Enter your answer, rounded to the nearest inch, in the box.

Let s = shorter side.

\(\begin{array}{|rcll|} \hline \tan(72^{\circ}) &=& \dfrac{12}{s} \\ s &=& \dfrac{12}{\tan(72)^{\circ}} \\ s &=& \dfrac{12}{3.07768353718} \\\\ s &=& 3.89903635479 \\ \hline \end{array}\)

\(s = 3.89903635479\ \text{inch}\)

The perimeter of the tile is:

\(\begin{array}{|rcll|} \hline && 2\times 12 + 2\times 3.89903635479 \\ &=& 24 + 7.79807270959 \\ &=& 31.7980727096\ \text{inches} \\ \hline \end{array}\)

The perimeter of the tile rounded to the nearest inch is 32 inch.

What does the fundamental theorem of algebra state about the equation ?

\(x = \dfrac{3 \pm i \sqrt{11}}{2}\) and the degree of the polynomial is 2.

Answer c

Factor the polynomial.

\((2 x - 3 y)(x + 2)\)

Jacob, in a world where dirty dogs like you can write, they can certainly talk.

Two chords, AB and CD meet inside a circle at P If AP = 3 and CP = 8 then what is BP/DP?

Two chords, AB and CD meet inside a circle at P If AP = 3 and CP = 8 then what is BP/DP?

\(\begin{array}{|rcll|} \hline AP \times BP &=& CP \times DP \\ 3\times BP &=& 8 \times DP \\\\ \dfrac{BP}{DP} &=& \dfrac{8}{3} \\ \hline \end{array}\)

Thank you CPhill

If the two roots of the quadratic $7x^2+3x+k$ are $\frac{-3\pm i\sqrt{299}}{14}$,

what is $k$?

\(\begin{array}{|rcll|} \hline 7x^2+3x+k &=& 0 \quad | \quad : 7 \\\\ x^2+\frac37x+ \underbrace{\frac{k}{7}}_{=x_1x_2} &=& 0 \\\\ \dfrac{k}{7} &=& x_1x_2 \quad | \quad x_1 = \dfrac{-3+ i\sqrt{299}}{14} \quad x_2 = \dfrac{-3- i\sqrt{299}}{14} \\\\ \dfrac{k}{7} &=& \dfrac{\left(-3+ i\sqrt{299}\right) }{14}\cdot \dfrac{\left(-3- i\sqrt{299}\right) }{14} \\\\ \dfrac{k}{7} &=& \dfrac{(-3+ i\sqrt{299})(-3- i\sqrt{299}) }{14\cdot 14} \\\\ \dfrac{k}{7} &=& \dfrac{9- i^2\cdot 299 }{14\cdot 14} \quad | \quad i^2 = -1 \\\\ \dfrac{k}{7} &=& \dfrac{9- (-1)\cdot 299 }{14\cdot 14} \\\\ \dfrac{k}{7} &=& \dfrac{9+\cdot 299 }{14\cdot 14} \\\\ \dfrac{k}{7} &=& \dfrac{308}{14\cdot 14} \\\\ k &=& \dfrac{7\cdot 308}{14\cdot 14} \\\\ k &=& \dfrac{7\cdot 22}{14} \\\\ k &=& \dfrac{ 22}{2} \\\\ \mathbf{k} & \mathbf{=} & \mathbf{11} \\ \hline \end{array}\)

For specific positive numbers $m$ and $n$,
the quadratics $16x^2+36x+56$ and $(mx+n)^2$ differ only in their constant term.
What is $mn$?

\(\begin{array}{|lrcll|} \hline 16x^2+{\color{red}36}x+56 \\ &&& (mx+n)^2 \\ &&=& m^2x^2+{\color{red}2mn}x+n^2 \\ \Rightarrow & 36 &=& 2mn \\ & mn &=& \frac{36}{2} \\ & \mathbf{mn} & \mathbf{=} & \mathbf{18} \\ \hline \end{array}\)

The answer is a little kindness goes a long way, and have a great day. 

they aren't lines. they can't be.

1) Since you cannot use 7s and 9s, therefore we have: 0, 1, 2, 3, 4, 5, 6, 8. Since repeats are allowed, then we have: 8^3 - 8^2 = 448 - 3-digit numbers that have no 7s or 9s in them.

Here is a list of them all:

{1, 0, 0} | {1, 0, 1} | {1, 0, 2} | {1, 0, 3} | {1, 0, 4} | {1, 0, 5} | {1, 0, 6} | {1, 0, 8} | {1, 1, 0} | {1, 1, 1} | {1, 1, 2} | {1, 1, 3} | {1, 1, 4} | {1, 1, 5} | {1, 1, 6} | {1, 1, 8} | {1, 2, 0} | {1, 2, 1} | {1, 2, 2} | {1, 2, 3} | {1, 2, 4} | {1, 2, 5} | {1, 2, 6} | {1, 2, 8} | {1, 3, 0} | {1, 3, 1} | {1, 3, 2} | {1, 3, 3} | {1, 3, 4} | {1, 3, 5} | {1, 3, 6} | {1, 3, 8} | {1, 4, 0} | {1, 4, 1} | {1, 4, 2} | {1, 4, 3} | {1, 4, 4} | {1, 4, 5} | {1, 4, 6} | {1, 4, 8} | {1, 5, 0} | {1, 5, 1} | {1, 5, 2} | {1, 5, 3} | {1, 5, 4} | {1, 5, 5} | {1, 5, 6} | {1, 5, 8} | {1, 6, 0} | {1, 6, 1} | {1, 6, 2} | {1, 6, 3} | {1, 6, 4} | {1, 6, 5} | {1, 6, 6} | {1, 6, 8} | {1, 8, 0} | {1, 8, 1} | {1, 8, 2} | {1, 8, 3} | {1, 8, 4} | {1, 8, 5} | {1, 8, 6} | {1, 8, 8} | {2, 0, 0} | {2, 0, 1} | {2, 0, 2} | {2, 0, 3} | {2, 0, 4} | {2, 0, 5} | {2, 0, 6} | {2, 0, 8} | {2, 1, 0} | {2, 1, 1} | {2, 1, 2} | {2, 1, 3} | {2, 1, 4} | {2, 1, 5} | {2, 1, 6} | {2, 1, 8} | {2, 2, 0} | {2, 2, 1} | {2, 2, 2} | {2, 2, 3} | {2, 2, 4} | {2, 2, 5} | {2, 2, 6} | {2, 2, 8} | {2, 3, 0} | {2, 3, 1} | {2, 3, 2} | {2, 3, 3} | {2, 3, 4} | {2, 3, 5} | {2, 3, 6} | {2, 3, 8} | {2, 4, 0} | {2, 4, 1} | {2, 4, 2} | {2, 4, 3} | {2, 4, 4} | {2, 4, 5} | {2, 4, 6} | {2, 4, 8} | {2, 5, 0} | {2, 5, 1} | {2, 5, 2} | {2, 5, 3} | {2, 5, 4} | {2, 5, 5} | {2, 5, 6} | {2, 5, 8} | {2, 6, 0} | {2, 6, 1} | {2, 6, 2} | {2, 6, 3} | {2, 6, 4} | {2, 6, 5} | {2, 6, 6} | {2, 6, 8} | {2, 8, 0} | {2, 8, 1} | {2, 8, 2} | {2, 8, 3} | {2, 8, 4} | {2, 8, 5} | {2, 8, 6} | {2, 8, 8} | {3, 0, 0} | {3, 0, 1} | {3, 0, 2} | {3, 0, 3} | {3, 0, 4} | {3, 0, 5} | {3, 0, 6} | {3, 0, 8} | {3, 1, 0} | {3, 1, 1} | {3, 1, 2} | {3, 1, 3} | {3, 1, 4} | {3, 1, 5} | {3, 1, 6} | {3, 1, 8} | {3, 2, 0} | {3, 2, 1} | {3, 2, 2} | {3, 2, 3} | {3, 2, 4} | {3, 2, 5} | {3, 2, 6} | {3, 2, 8} | {3, 3, 0} | {3, 3, 1} | {3, 3, 2} | {3, 3, 3} | {3, 3, 4} | {3, 3, 5} | {3, 3, 6} | {3, 3, 8} | {3, 4, 0} | {3, 4, 1} | {3, 4, 2} | {3, 4, 3} | {3, 4, 4} | {3, 4, 5} | {3, 4, 6} | {3, 4, 8} | {3, 5, 0} | {3, 5, 1} | {3, 5, 2} | {3, 5, 3} | {3, 5, 4} | {3, 5, 5} | {3, 5, 6} | {3, 5, 8} | {3, 6, 0} | {3, 6, 1} | {3, 6, 2} | {3, 6, 3} | {3, 6, 4} | {3, 6, 5} | {3, 6, 6} | {3, 6, 8} | {3, 8, 0} | {3, 8, 1} | {3, 8, 2} | {3, 8, 3} | {3, 8, 4} | {3, 8, 5} | {3, 8, 6} | {3, 8, 8} | {4, 0, 0} | {4, 0, 1} | {4, 0, 2} | {4, 0, 3} | {4, 0, 4} | {4, 0, 5} | {4, 0, 6} | {4, 0, 8} | {4, 1, 0} | {4, 1, 1} | {4, 1, 2} | {4, 1, 3} | {4, 1, 4} | {4, 1, 5} | {4, 1, 6} | {4, 1, 8} | {4, 2, 0} | {4, 2, 1} | {4, 2, 2} | {4, 2, 3} | {4, 2, 4} | {4, 2, 5} | {4, 2, 6} | {4, 2, 8} | {4, 3, 0} | {4, 3, 1} | {4, 3, 2} | {4, 3, 3} | {4, 3, 4} | {4, 3, 5} | {4, 3, 6} | {4, 3, 8} | {4, 4, 0} | {4, 4, 1} | {4, 4, 2} | {4, 4, 3} | {4, 4, 4} | {4, 4, 5} | {4, 4, 6} | {4, 4, 8} | {4, 5, 0} | {4, 5, 1} | {4, 5, 2} | {4, 5, 3} | {4, 5, 4} | {4, 5, 5} | {4, 5, 6} | {4, 5, 8} | {4, 6, 0} | {4, 6, 1} | {4, 6, 2} | {4, 6, 3} | {4, 6, 4} | {4, 6, 5} | {4, 6, 6} | {4, 6, 8} | {4, 8, 0} | {4, 8, 1} | {4, 8, 2} | {4, 8, 3} | {4, 8, 4} | {4, 8, 5} | {4, 8, 6} | {4, 8, 8} | {5, 0, 0} | {5, 0, 1} | {5, 0, 2} | {5, 0, 3} | {5, 0, 4} | {5, 0, 5} | {5, 0, 6} | {5, 0, 8} | {5, 1, 0} | {5, 1, 1} | {5, 1, 2} | {5, 1, 3} | {5, 1, 4} | {5, 1, 5} | {5, 1, 6} | {5, 1, 8} | {5, 2, 0} | {5, 2, 1} | {5, 2, 2} | {5, 2, 3} | {5, 2, 4} | {5, 2, 5} | {5, 2, 6} | {5, 2, 8} | {5, 3, 0} | {5, 3, 1} | {5, 3, 2} | {5, 3, 3} | {5, 3, 4} | {5, 3, 5} | {5, 3, 6} | {5, 3, 8} | {5, 4, 0} | {5, 4, 1} | {5, 4, 2} | {5, 4, 3} | {5, 4, 4} | {5, 4, 5} | {5, 4, 6} | {5, 4, 8} | {5, 5, 0} | {5, 5, 1} | {5, 5, 2} | {5, 5, 3} | {5, 5, 4} | {5, 5, 5} | {5, 5, 6} | {5, 5, 8} | {5, 6, 0} | {5, 6, 1} | {5, 6, 2} | {5, 6, 3} | {5, 6, 4} | {5, 6, 5} | {5, 6, 6} | {5, 6, 8} | {5, 8, 0} | {5, 8, 1} | {5, 8, 2} | {5, 8, 3} | {5, 8, 4} | {5, 8, 5} | {5, 8, 6} | {5, 8, 8} | {6, 0, 0} | {6, 0, 1} | {6, 0, 2} | {6, 0, 3} | {6, 0, 4} | {6, 0, 5} | {6, 0, 6} | {6, 0, 8} | {6, 1, 0} | {6, 1, 1} | {6, 1, 2} | {6, 1, 3} | {6, 1, 4} | {6, 1, 5} | {6, 1, 6} | {6, 1, 8} | {6, 2, 0} | {6, 2, 1} | {6, 2, 2} | {6, 2, 3} | {6, 2, 4} | {6, 2, 5} | {6, 2, 6} | {6, 2, 8} | {6, 3, 0} | {6, 3, 1} | {6, 3, 2} | {6, 3, 3} | {6, 3, 4} | {6, 3, 5} | {6, 3, 6} | {6, 3, 8} | {6, 4, 0} | {6, 4, 1} | {6, 4, 2} | {6, 4, 3} | {6, 4, 4} | {6, 4, 5} | {6, 4, 6} | {6, 4, 8} | {6, 5, 0} | {6, 5, 1} | {6, 5, 2} | {6, 5, 3} | {6, 5, 4} | {6, 5, 5} | {6, 5, 6} | {6, 5, 8} | {6, 6, 0} | {6, 6, 1} | {6, 6, 2} | {6, 6, 3} | {6, 6, 4} | {6, 6, 5} | {6, 6, 6} | {6, 6, 8} | {6, 8, 0} | {6, 8, 1} | {6, 8, 2} | {6, 8, 3} | {6, 8, 4} | {6, 8, 5} | {6, 8, 6} | {6, 8, 8} | {8, 0, 0} | {8, 0, 1} | {8, 0, 2} | {8, 0, 3} | {8, 0, 4} | {8, 0, 5} | {8, 0, 6} | {8, 0, 8} | {8, 1, 0} | {8, 1, 1} | {8, 1, 2} | {8, 1, 3} | {8, 1, 4} | {8, 1, 5} | {8, 1, 6} | {8, 1, 8} | {8, 2, 0} | {8, 2, 1} | {8, 2, 2} | {8, 2, 3} | {8, 2, 4} | {8, 2, 5} | {8, 2, 6} | {8, 2, 8} | {8, 3, 0} | {8, 3, 1} | {8, 3, 2} | {8, 3, 3} | {8, 3, 4} | {8, 3, 5} | {8, 3, 6} | {8, 3, 8} | {8, 4, 0} | {8, 4, 1} | {8, 4, 2} | {8, 4, 3} | {8, 4, 4} | {8, 4, 5} | {8, 4, 6} | {8, 4, 8} | {8, 5, 0} | {8, 5, 1} | {8, 5, 2} | {8, 5, 3} | {8, 5, 4} | {8, 5, 5} | {8, 5, 6} | {8, 5, 8} | {8, 6, 0} | {8, 6, 1} | {8, 6, 2} | {8, 6, 3} | {8, 6, 4} | {8, 6, 5} | {8, 6, 6} | {8, 6, 8} | {8, 8, 0} | {8, 8, 1} | {8, 8, 2} | {8, 8, 3} | {8, 8, 4} | {8, 8, 5} | {8, 8, 6} | {8, 8, 8} (total: 448)

If the numbers after x or y is powers, then they aren't lines.

\(7*\frac{2}{3}=\frac{14}{3}\). The smallest integer greater than 14/3 is \(5\)

Let us have republicans called R and Democrats called D. We can have RRRRRDDDD, RRRRDDDDR, RRRDDDDRR, RRDDDDRRR, RDDDDRRRR, and DDDDRRRRR. Notice that all cases have the same amount of arrangments. So the ways the committee members can sit is \(4!*5!*6=17280\).

OK. This is my understanding of this:

You cannot use 2, 3, 4, 5 in any number. Therefore you are restricted to: 1,0, 6, 7, 8, 9.

Since repeats are allowed, we then can have: 6^4  - 6^3 =1,080 - 4-digit numbers. 

Then we can have: 6^3 - 6^2 =180 - 3-digit numbers.

Then we can have: 6^2 - 6^1 =30 - 2-digit numbers

Finally, we can have: 6^1 - 6^0 =5 - 1-digit numbers. So, in total, we should have:

1,080 + 180 + 30 + 5 =1,295 numbers that have no 2, 3, 4, 5 in them. 

Note: The reason for the subtractions is that no number is allowed to begin with "0".

I will use numbers only. You draw the diagram!!

Just multiply: 7 people x 2/3 =14 / 3 = 4 2/3 = 5 - pizzas - since you can't order 2/3 of a pizza!!.

5 - 4 2/3 = 1 / 3 of a pizza will be "leftover"!.

6)

No, it is not a geometric series. It is a simple "word problem!"

Since they want to raise $350 in one day and the owner contributes $20, then they need to raise:

$350 - $20 = $330 from the sale of coffee.

$330 / 2,200 =$0.15 - or 15 cents per cup of coffee.