3^(2x + 2) + 27^(x + 1) = 36 we can write
[ 3^2] ^(x + 1) + [3^3]^(x + 1)] = 36 factor the left side
[3^2]^(x + 1) [ 1 + 3] = 36
[3^2]^(x + 1) [4] = 36 divide both sides by 4
[3^2]^(x + 1) = 9
[9]^(x + 1) = 9^1
Since the bases are the same, solve for the exponents
x + 1 = 1 subtract 1 from both sides
x = 0
