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Thanks Chris.

which of the two is the right answer?

2Ca(s) +4 H2O(I)  =  2 Ca(OH)2(aq)+2H2(g)      I added the ' = '

94 =F + 26D,  
27 =F + 93D, solve for F, D
F =120 - First term
D = -1 - Common difference

2, you have detailed answer.

angle addition postulate

alternate exterior angles

definition of a bisector

substitution property of equality

Equation: \(4x+5=13, 4x=8, \boxed{x=2}.\)

Good solution, but it's \(5*5, \) not \(5.5\) .

Hey, Manuel! What's up?

Thank you, everyone! 

To   have integer solutions.....the discriminant must  either possibly  = 0   or possibly be a  perfect square.....so

a^2 - 4(5a) = 0

a^2 - 20a  =  0

a ( a - 20) = 0

Setting each factor to 0 and solving for a   produces  a =  0   or  a = 20

Or

a^2 - 20a   = perfect square

a (a - 20)  = perfect square

This happens when   a = 20  , a = 0 , a = -16  or a  =  36

So....4 values for a  produce integer solutions

x/8 - 1/6   = 1/12         write  1/6 as 2/12

x/8 - 2/12 = 1/12    add 2/12 to oth sides

x/8 =  3/12 

x/8  = 1/4       cross-multiply

4x = 1*8

4x = 8     divide both sides by 4

x = 2

Rotate 180 degrees about the origin

Translate 2 units right

To see this...look at  A   = (-1, 2)

Reflecting across the line 180 degrees about the origin reverses the signs of the coordinates = (1, -2)

Translating this two units to the right produces (3,-2)  = A '

Check the other two points to see this is true....

I know right??

Move −25-25.

10a+5b−25

D.  preimage

Correct....!!!

I believe that  C is correct, NSS...

Hey long time no see!

Welcome back MB!! Its been awhile!!

C.

5 lines of symmetry

I believe that   6 is correct, NSS.....

The ratio of the side lengths is a linear comparison....this is just the scale factor  = 1 / 3

Ratio of surface areas =  (scale factor)^2  = (1/3)^2  =  1/9