Here's another way to do this with similar triangles....it is much easier
First....calculate DE as I did before = 6.5
Note that angle BXC = angle DXE (vertical angles)
Angle DEX = Angle CBX (alternate interior angles between parallels )
So triangle BXC is isimilar to triangle EXD
Since base ED is 1/2 of BC
Then the height of triangle EXD is 1/2 that of triangle BXC
So y = 4.5 is split into tree equal parts....and the height of BXC is (2/3)of these = 3
Then area of triangle EXD = 1/4 area of triangle BXC
Area of BXC = (1/2)(3)(13) = 39/2 = 19.5
And the area of EXD = (39/8)
And the area of triangle ADE is (1/2)(4.5)(6.5) = (117/8)
So the area of AEXD = area of triangle EXD + area of triangle of triangle ADE =
(39/8 + 117/8) = (156/8) = 19.5
So the ratios of BXC / AEXD = 19.5 /19.5 = 1
![cool cool](/img/emoticons/smiley-cool.gif)
![cool cool](/img/emoticons/smiley-cool.gif)