All Answers 358090 Answers

The area to the LEFT of the center of the circle is given by

1km x . 8km  = .8km^2

Subtract the 1/2 circle area :   - 1/2 pi (.8km/2)^2 = - .2513 km^2

.8 - .2513 = .5486 km^2

Total rectangular area is      (1+1.4)km x (.8 km) = 1.92 km^2

.5486 km^2/ 1.92 km^2 = .286   = 28.6 % chance of landing in that little area...

Was pretty dreadful

Snowvember

Sorry for interupting but I am extremly impressed with your math abilities its almost like you know it all XD are you already done with school and do this as a leisure to help people?

Me thinks you are talking about WINDCHILL.....which is not the actual temp.  

        The record low for MN was -60 in Feb 1996. 

I don't think I could ever go back to the cold

\(\left(2a^2b=5b^3+4a^4b^2\right)-\left(7b^3+8a^4b^2-7a^2b\right)\)

simplify

\(\left(2\cdot \:5=a^2b^3b+4a^4b^2\right)-\left(7b^3+8a^4b^2-7a^2b\right)\)

simplify

\(\left(2a^2b=5b^3+4a^4b^2\right)-7b^3-8a^4b^2+7a^2b\)

How do I post it as latex??

Can you post this as latex instead?

Factors of 700   :    1,2,4,5,7,10,14,20,25,28,35,50,70,100,140,175,350,700

Maybe the ones in red?   Like answer is 8??

Multiples of 7 that exceed  what ???

First one.....we write  the terms in descending powers of   m......so we have

4m^3 - 9 m^2 - m + 25     (cubic polynomial)

Second one  ...... same thing ....descending powers of k  ....so we have

(3/4)k^5  - (1/2)k^3       (quintic polynomial)

Third one.....this is a polynomial  in two variables

The form is     ax^2 + bxy + cy^2 + dx + ey + f 

So we have

-x ^2   -3xy  + 14y^2    (second power polynomial)

Last one.....nothing to be done.....there's no other way to write 9x  ( first degree polynomial )

5.6^(-5) * 3.4^(-7) * 5.6^(3) * 3.4^(-4)  =

 5.6^(-5) * 5.6^(3) * 3.4^(-7) * 3.4^(-4)        { we are using the rule a^m * a^n = a^(m + n)   }

5.6^(-2) * 3.4^(-11)

Here's a graph of the first one :   https://www.desmos.com/calculator/oqouuljrdk

Second one :  The graph at the top left is the correct one

Third one :   f(x)  =  10cos  [ (pi/2) x ] + 10    is correct

Last one :  f(x) = 9 sin ( 6pi x) + 3    is correct

Well, I'll take Tennessee over Indiana right now. You probably have more snow and rain then what we have here.

That’s how Indiana is!

Wow thats pretty crazy

OK.....glad to help....!!!

Yah....back in CO......Dallas last week.....Minnesota the week before that (when it was -30 cool)....   took the dogs for a few runs in the -20 range.....we didn't go very far !