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8x+47 does not equal 8(x+6) because 8*x=8x and 8*6=48

We could try to simplify 8x+47=8x+48 but since it already doesn't match, it won't get us anywhere.

Subtract 47 from both sides to get 8x=8x+1

Subtract 8x from both sides which gets you 0=1 which certainly does not equal eachother. 

So, therefore, there are no solutions to this equation. 

Ohhh okay, thank you!

Thanks CPhill, and you're very welcome raziel!

Okay so I would have to do 2*4 and that would be 5x+4=234

And eventually I would get 46

For the next one...I'm not sure actually. 17x-20+268=360??

omg thanks i really needed that!

Very nice, RP !!!!

The firts step to solving this problem would be to group like terms which is the same as C: Collect like terms so it's not C. It's also not D because that is also kind of the same thing because we only collected the terms on on side. We also have to isolate the variable. 

7x+15-15=24+4x-15

7x=4x+9

7x-4x=4x+9-4x

3x=9

Divide by 3 on both sides

x=3

The only thing we didn't do was use distrubituve property. So the answer is A

OK.....

1  the arc C  all of the way around to A   is   2 * (5x+2)      

           This same arc is equal to 360 - 87 - 39     Right?   Can you do it now?

2  ARC YZ = 2 * 59     This plus  the 75 degree arc      =   2 * 59 + 75

                                                      THIS plus the  17x-20 arc = 360 degrees (the entire circle)

                                                 so  2 * 59 + 75   + 17x -20 = 360     Right?  Need more?

9 is correct

Let's look at the second one

(7x + 9) * 2 =  46      divide both sides by 2

7x + 9 =  23           subtract 9 from both sides

7x = 14

x = 2

In general

"Surface" area usuall refers to total surface area of an object

"Lateral" surface area is the total area less the areas of the "top" and "bottom" of an object

For example....the lateral surface area of a soup can is just the area of the label

The total surface area also includes the area of the top and bottom

No problem ^-^

THANKS :D

2x+4=16

-4       -4

2x=12

/2    /2

x=6

So B is the answer :)

Yes, thank you! I got 9 and 4

First one....  the arc encompassed by an inscribed angle is TWICE the angle...

   so  16x -10  =  2 * 67

Is that enough help?

Second one   (7x+9) * 2  =46    See that  2 again?

Correct !!!

thanks math god

Agreed....all those lines make me crazy, too!!!

x+ 20+10x = 20 + 9x      simplify each side

11x + 20  = 20 + 9x       subtract  9x, 20 from both sides

2x = 0      divide  both sides by 2

x = 0

We are only really using two theorems here

1)   Opposite angles in a cyclic quadrilateral  sum to 180°

2)  The measure of an inscribed angle =  (1/2) the measure of the arc it intercepts

Second one

Notice that angle Q intercepts  arc PSR

And the measure of this arc= 137 + 41  =  178°

And because angle Q is an inscribed angle intercepting this arc...it measures (1/2)(arc PSR) = (1/2)(178) = 89°

We have a cyclic quadrilateral....R is supplemental to 57°  =  180 - 57  =  123°

And S is supplemental to Q =   180 - 89  =  91°

These are all answered so differently. How am I supposed to know which formula to use for each problem?

Hey, RP....good to see you !!!

First one

We have a quadrilateral inscribed in a circle  (a cyclic quadrilateral).....whenever this is so....the opposite angles in the quadrilateral are supplementary (the sum to 180°)

So 

 A + C = 180

A  + 101 = 180    subtract  101 from both sides

A = 79°

Smillarly

B + D = 180

B + 68 = 180

B = 180 - 68

B = 112°

Solve for x:
1/625 = 5^(-12/x)

1/625 = 5^(-12/x) is equivalent to 5^(-12/x) = 1/625:
5^(-12/x) = 1/625

Take reciprocals of both sides:
5^(12/x) = 625

Take the logarithm base 5 of both sides:
12/x = 4

Take the reciprocal of both sides:
x/12 = 1/4

Multiply both sides by 12:

x = 3