All Answers 356463 Answers

Second one

Avg rate of change  [2, 5 ]  =  [ 110 - 92 ] / [ 5 - 2 ]  = 18 / 3  =  6

Last one

At x = 3,  y ≈ 3.5

At x = 6, y = 9

So....the avg rate of change is   [ 9 - 3.5 ]  / [ 6 - 3 ]  =   5.5 /3  =  55 / 30  =   11 / 6

First one

Avg rate of change on [ a, b ]  =  [ g(b)  - g(a)] / [ b - a]

So....on  [ -3, - 1]   we have  [ 9 - 5] / [ -1 - (-3) ] =   4/ 2  = 2

[-1, 1 ] is correct

[ 1, 3 ]  =   [ 13 - 17 ] / [ 3 - 1 ]  =   -4/ 2  =  -2

[ 3, 4 ] is correct

Thank you so much for the help. I really appreciate your help with this!

1.   If  x - a is a factor, then the remainder when P(x) is divided by x- a  will be 0

[ A "factor" of a polynomial means that it divides the polynomial evenly....there will be a remainder of 0 ]

2. What will be the remainder when the polynomial p (x ) = 3x 5 - 8x 3 + 4x 2 - 41 is  divided by x - 2?

If a polynomial  is divided by  x - a.....then the remainder   will =  P(a).....in other words....we put "a" into the polynomial  and evaluate.....the evaluation will be the remainder

So......x - a  = x -2      ....so....we put 2 into the polynomal  and we get

3(2)^5  - 8(2)^3  + 4(2)^2   - 41  =

3*32  - 8*8 + 4*4  - 41 =

96 - 64 + 16 - 41  =

7 =   the remainder

3. If the binomial (x-7) is a factor of the polynomial function f(x), which statement must be true?

If  x - a  is a factor....then "a"  is a zero....so  P(a) = 0

In this case.....x - 7 is a factor.....so......7 is a zero......so....P(7) = 0

thank you so much for teaching me 

ok... 

so TE = 116 + (58*9.81*6) = 5921.8

my gpe under 6M: .(58*9.81*6)= 3529.88

5805.8 - 3529.88 = 2275.92

2507.2 = 1/2 58v^2

86.48= v^2

v= 9.3 ms^-1

Dude haven't we already been here I mean you did get called out. like how much do you need to cheat on the gravity and energy module. Learn how to get Honest answers

Thanks so much! I appreciate the help!!!

Correct for the first one, guest....I missed the dot

No....Plane A travels farther in one hour than Plane B

That is a solid dot at zero....so zero is included ....first Q should be answer  #4  or  D

Q 2  is the first choice    A>B in 1 hour

Thank you so much for your help!! 

First one.....if   a/b   is a root, then  (bx - a) is a factor

To see this   let  bx - a = 0

Then  bx = a

And  x  = a/b  is  the root

So....if 3/4 is a root, then,  (4x - 3)  is a factor

Second one

x^2 - 4 =  0     factor as

(x + 2) ( x - 2)  = 0

So....this will have two roots  (zeros)

Last one

If  x - a  divides P(x).....then  a is a  zero   (root)   ...so.....  P(a) = 0

So

If x - 2 divides P(x)......then 2 is a zero   ....so....P(2)  = 0

So CPhill, according to your explanation for the second question, the second choice would be correct?

First one - last choice

Second one

Plane A travels 290 (1 hr)  =  290 miles  in one hour

Plane B  travels 540 / 2hrs  = 270 miles in one hour

Last one

Function A has  a vertical asymptote  where  x - 3 =  0  ⇒   at   x = 3

Function B has a vertical asymptote at x  = 4

Total energy (TE) = Kinetic energy (KE) + Potential energy (PE)

KE = (1/2).m.v², where m is mass and v is velocity

PE = m.g.h, where g is gravitational acceleration and h is height (above pool surface).

Calculate TE at diving platform (you have already calculated the KE there).

Work out the PE at the point 6metres below the platform.

Then, because TE is conserved, you can set (1/2)mv² + PE_{at6metresbelowplatform}= TE, where v is now the velocity at 6m below the platform. This v is the only unknown, so you can rearrange the equation to find it.

Incidentally, you should really give your results with units: Joules for energy, metres/sec for velocity.

you should chose D

YEs you did

Thank you very much

It will be even

1*2*3*4*5  =  120  would be divisible by every integer from 1 - 10  inclusive except for 7 and 9

Multiplying this by 3  gives

1*2*3*3*4*5  =     1* 2*4*5*9  =  360

This will be divisible  by 1, 2, 3, 4, 5, 6, 8, 9, and 10......it will not be divisible by 7

Sorry....this Q makes no sense..... what info did you omit?

If you meant    pi r^2 h    then just substitute in the values given and calculate....silly!