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The mean is the average of the numbers, which means add them all up, and then divide them by how many numbers there are. So we have \(\frac {35+34+32+16+45+38+28}{7} = \frac {228}{7}\) . You could reduce this number more, but it's an infinite number. 

Hope this helps!

1. See the graph here, PF  :  https://www.desmos.com/calculator/xshyczl312

The solutions occur at x = -3   and x = 1

2.   2x^3 + 3x

If  we can put -x  into the function and come back to what we started with...it is even

So..... 2(-x)^3 + 3(-x)   =   -2x^3 - 3x = f(-x)  ......not what we started with...so..not even

If  f(-x) = -f (x) ......then it is odd

-f(x)  =  - [ 2x^3 + 3x ]  =  -2x^3 - 3x   = f(-x)....so...it's odd

3.  (f + g) x  means  f(x) + g(x)  =  [ x^2 - 36 ] + [ x^3 + 2x^2 -10 ]  = x^3 + 3x^2 - 46

You can also just put this equation into a calculator, and most will give you the answer in scientific notation, like BaldisBasics

Area of a circle = \(\pi r^2\) . So we have 36\(\pi\) . But that's assuming that there is 360 degrees in the circle. So we have \(\frac {48}{360} \cdot 36\pi = \frac {1728\pi}{360} = 4.8\pi\) .

Thank you so much! I will definetly study these types of problems harder. Thank you!

im new on this whole thing in i really need help with my work im having a hard time understanding

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NO PICTURE!.

maybe but this is my morning math with no calc so I test if I get the same answer as you

a what?

what does it =

Percentage increase is given by [(2nd order/1st order) - 1]*100

Real question is do they taste good.....

Try to restart you device and try again

Thank you, CPhill.

Yep

I got 10 desirable outcomes out of a total of 32 possible options which is  10/32  =   5/16     

Method:

The first digit must be 7 then there are 5 more digits with 2 posibilities each so there are    2^5 = 32 possible numbers.

If a number is divisable by 77 then it must be divisable by 7 and 11.

Since all the digits are either 0 or 7 all the numbers will be divisable by 7 so I need to worry about if it is divisable by 11.

Now I looked up the internet fo find tricks for deciding if a number is divisable by 11.

This is what I found.