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Amplitude of the wave   (actuallt the SQUARE of the amplitude)

We have an arithmetic series

The first term =  98 - 2(1) = 96

The 11th term is   98 - 2(11) = 76

The sum is given by :

[ first term + 11 term ] * ( number of terms) / 2  =

[ 96 + 76 ] ( 11) / 2  =

172 * 11/ 2  =

(172 / 2 ) * 11 =

(86) * 11

946

This is a geometric series

The first term =  5

The common ratio is -2

The sum of the first five terms is

first term [  1 - common difference^5] / [ 1 - common difference ]

5  [ 1 - (-2)^5 ] / [ 1 - (-2) ]  =

5 [ 1 + 32 ]  / [ 3]  =

5 { 11]  = 

55

Area_sector  =  (1/2) radius^2  * ( theta in radians)

So

(1/2) (2)^2 ( pi/3)  =

(2/3) pi   cm^2

We have a geometric series......the sum of the first 6 terms is

first term [ 1 - common ratio^n ] / [ 1 - common ratio  ]       

Where n  = 6   and the common ratio  =  2

So  we have

8 [ 1 -  2^6] / [ 1 - 2 ]  =

8 [ -63] / -1  =

8 * 63  =

504 

The words are amplitude and frequency, in that order. 

.

It's \(\pi r(r+\sqrt{h^2+r^2})\), where r= the radius and h= the height.

You are very welcome!

:P

Well, yeah, that's cool

a_n= 5(-2)^n-1

Recursive rule :

an = (-2) a_n-1        a₁  = 5

I believe you're going to have to solve this numerically.

The solution is approximately 2.276

Thanks, Rom.....there is one more value of k......

If the discriminant is 0, we also have a rational solution  (root)

So

10^2 -  4k^2  = 0

100 = 4k^2

25  = k^2

5 = k 

Good point, thanks

I was gonna say Oscillation, but that works too. Good job!

frequency

wavelength

If you have basic problems like this, then you might find a calculator more useful than a forum. However, the answer is 73456512. Just plug it into a calculator, and there you have it.

Hope this helps!

Mine was fun 3 different appts.

in a row,

dentist

physical

sports physical 

lol

We have a geometric series.....the common ratio   is    16/ - 8  = -2

The sum of the first n terms is given by:

first term  [  1 -  common ratio^n  ] / [ 1  - common ratio ]         

So.....the  sum is

-8 [ 1 - (-2)^(7) ] / [ 1 - (-2) ]  =

-8 [  1  -  (-2)^7]  / [ 3 ]   =  

-8 (129) / 3  =

-8 ( 43)  =

-344

Thanks so much!!!

2c: Why is the AA Postulate not likely to be the tool Quincy needs? (2 points)

Without knowing the length of JL.....we cannot determine any of the angles in triangle JKL

4.80 x 10²