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Melody, it matters to me because I'm learning from this site.  You are so bright, I am astonished by how smart you are.  The other moderators, as well.  The tone of your remarks to me in this thread seems more forceful than warranted.  I haven't been criticizing you, nor challenging you; I just thought I could help, in my small way, albeit very small.  I get the impression that my ideas are unwelcome.

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Hello LMessiA,

It is very nice to meet you.    

For starters you do what you just did, say thank you and whenever possible add something to it. 

That is communication 

Answerers really like it when their answers are questioned. 

Most of the time we feel like we are teaching brick walls. Polite interaction is always appreciated.

Also if you hover the curser over the heart in the top right of a post you can see a + and a - 

By pressing the appropriate one you can increase or decread their score by one.

Remeber that people are trying to help, even if the answer is nonsense it still would rarely deserve a down vote.

I hope you learn a lot from the wonderful answerers who haunt this forum and that you enjoy the experience as well. :)

Any questions?  Well just ask :)

Thank you for telling me that I'm right! I'm sorry for not giving people credit that answers my questions. I don't know how to give them credit. How do I do that?

Hi LmessiA,

I just looked at your track record. 

You have been answered on 3 previous threads.

You have only ever said thank you once for an answer.

You do not give point credit to your answerers.

You have never commented in any other way, other than that one thank you.

   If you want answers to explain in more detail then you need to interact with them.

I am letting you know that your manners and attitude are under watch.

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Having said all that negative stuff I will also add that it is good that you gave your answer of 30%.

It is good to see that people have tried to answer questions for themselves  

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Yes 12/40  is 30%  so this does seems a reasonable estimate based on the very limited fact that you have been given. 

Thanks Alan :)

Melody, for "the back to front e thingy" read "such that".

Find the integer \(n,\ 0 \le n \le 5\), such that \(n \equiv -3736 \pmod{6}\).

Find the integer \(n\), \(0 \le n \le 5\), such that \(n \equiv -3736 \pmod{6}\).

\(\begin{array}{|rcll|} \hline \mathbf{n} &\mathbf{\equiv}& \mathbf{-3736 \pmod{6} } \\\\ n +3736 &=& 6m \quad | \quad m\in \mathbb{Z} \\ n &=& 6m -3736 \quad | \quad m=\left\lfloor\dfrac{3736}{6} + 1 \right\rfloor \\ n &=& 6\left\lfloor\dfrac{3736}{6} + 1 \right\rfloor -3736 \\ n &=& 6\cdot 623 -3736 \\ n &=& 3738 -3736 \\ \mathbf{n} &\mathbf{=}& \mathbf{2} \\ \hline \end{array}\)

Do your own homework. 

Find the integer \(n, \;\;where \;\;\;0 \le n \le 5, \,\;\;such\; that \;\;n \;\equiv -3736 \pmod{6}. \)

-3736/6 = -622.6666666666666667 = -622+ - 4/6

n=-4mod6 = (-4+6) mod 6 =    2 mod 6

n=2

Edited: I made a super stupid careless error.  

Hi Rom,

What is the back to front e thingy ?

\(\text{Find }0 \leq n < 18 \ni n \equiv -11213141 \pmod{18}\)

\(\dfrac{11213141}{18} = 622952 + \dfrac{5}{18} \text{ so }\\ -11213141 + 622953\cdot 18 = 13 \equiv -11213141 \pmod{18}\)

whoops i'm an absolute idiot for not seeing that...thanks

72/9=s

Th question is asking you 

How many different times is the y value  equal to -1.

You can answer that.

Please no one state the final answer over the top of me.

\(\text{If rain and lightning are independent then }\\ P[\text{rain AND lightning}]=P[\text{rain}]P[\text{lightning}]\\ 0.15 \neq 0.6 \cdot 0.3 = 0.18\\ \text{that's choice C}\)

\(P[\text{rain AND lightning}] = \\ P[\text{lightning |raining}]P[\text{raining}] = \\ (0.1)(0.6) = 0.06 = 6\%\\ \text{Choice B}\)

EP calculated the first one on the basis of "simple interest". In other words, "not compounded"

If you compound it, then you would have:

$400 x 1.08^4 = $544.20

$544.20 - $400 =$144.20 - interest earned on the investment.

I think this is a past asked question. Maybe it would be helpful to check it out here!