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"Given is the function f(x) = -3x + 2 

a. The graph of g starts from the graph of f by multiplying the x axis with the factor - 2/3 and shift it up 1/3. What is the function notation of g?

b. The graph of the function h(x) = -12x + 10  starts from the graph of f by multiplying the x axis and then shift it. With which factor do you have to multiply and how does the graph translate. 

c. The graph of h can also start from the graph of f by first translating and then multiplying. Show how. "

Is this what you are looking for:

I don't quite understand how to solve a and c, but I already kinda started on b but I don't know how to continue

the shift of f is u

-12x + 10 + u = -3x + 2

12x + u = 3x -8

4x + u = x + -8

"Let A be a 2*2 matrix such that det(A) = 7. Find det(3A)"

Translated in English: 

To change a decimal to a fraction you would have to know how many places are after the decimal. Depending on the place of the numbers after the decimal it depends on how you will create that fraction. 

For example:

If you had 1.5 and had to transform it into a fraction, look at the 5 which is after the decimal point. It is in the tenths place. So you would take it and: 

\(\frac{1.5}{1}*\frac{10}{10}=\frac{15}{10}\)

That would be the fraction then simplify it by dividing it by its greatest common factor (GCF) which is 5:

\(\frac{15÷5}{10÷5}=\frac{3}{2}\)

This would be a improper fraction and if needed it could be put into a mixed number:

\(\frac{3}{2}=1\frac{1}{2}\)

You would be able to use this method for any decimal. Just make sure you understand what place the last decimal to the right would be. If its in the hundreths place then multiply it by 100/100, like when it was multiplied by 10/10 since it was in the tenths place. 

Hope this Helps ;P

Para cambiar un decimal a una fracción, deberías saber cuántos lugares están después del decimal. Dependiendo del lugar de los números después del decimal, depende de cómo crearás esa fracción.  

Por ejemplo: Si tenía 1.5 y tuvo que transformarlo en una fracción, mire el 5 que está después del punto decimal. Está en el décimo lugar. Así que lo tomarías y:

\(\frac{1.5}{1}*\frac{10}{10}=\frac{15}{10}\)

Esa sería la fracción, luego simplifíquela al dividirla por su máximo factor común (MFC), que es 5:

\(\frac{15÷5}{10÷5}=\frac{3}{2}\)

Esta sería una fracción impropia y, si fuera necesario, se podría colocar en un número mixto:

\(\frac{3}{2}=1\frac{1}{2}\)

Podrías usar este método para cualquier decimal. Solo asegúrate de entender en qué lugar estará el último decimal a la derecha. Si está en el lugar de los centésimos, multiplíquelo por 100/100, como cuando fue multiplicado por 10/10 ya que estaba en el lugar de los décimos.  

Espero que esto Ayude ;P

Usando la función f(x)=x^4+〖2x〗^3-6x^2+3x-5 encuentra el cociente y el residuo de dividirla entre las siguientes funciones.
x-1      x+5     -x+3

Did you check under yesterday's first post?

You got the answer right at this step:

73 / 76 * sqrt(2) . How did you "factor out" 73?

\(\frac{1}{\sqrt{2}+\frac{1}{\sqrt{8}+\sqrt{200}+\frac{1}{\sqrt{18}}}}\)

First, simplify the radicles in the expression

\(\sqrt{8}=\sqrt{2 \cdot 2\cdot 2} =2\sqrt{2}\)

\(\sqrt{200}=\sqrt{10\cdot20\cdot2}=10\sqrt{2}\)

\(\sqrt{18}=\sqrt{3\cdot3\cdot2}=3\sqrt{2}\)

\(\frac{1}{\sqrt{2}+\frac{1}{2\sqrt{2}+10\sqrt{2}+\frac{1}{3\sqrt{2}}}}\)

The two radicles can be added together because they have the same base

\(\frac{1}{\sqrt{2}+\frac{1}{12\sqrt{2}+\frac{1}{3\sqrt{2}}}}\)

Now start simplifying from the innermost fraction

Find a common denominator to add the two on the bottom

\(\frac{1}{\sqrt{2}+\frac{1}{\frac{73}{3\sqrt{2}}}}\)

\(\frac{1}{\sqrt{2}+\frac{3\sqrt{2}}{73}}\)

Find a common denominator again

\(\frac{1}{\frac{73\sqrt{2}}{73}+\frac{3\sqrt{2}}{73}}\)

Add the fractions

\(\frac{1}{\frac{76\sqrt{2}}{73}}\)

\(\frac{73}{76\sqrt{2}}\)

Multiply by \(\frac{\sqrt{2}}{\sqrt{2}}\) to get the radicle out of the denominator

\(\boxed{\frac{73\sqrt{2}}{152}}\)

46,620 =35 x 36 x37

[35 + 36 + 37] / 3 = 36 - the mean.

Let the full tank = T

Solve for T:
T/6 + 130 = (3 T)/5
Put each term in T/6 + 130 over the common denominator 6: T/6 + 130 = T/6 + 780/6:
T/6 + 780/6 = (3 T)/5
T/6 + 780/6 = (T + 780)/6:
(T + 780)/6 = (3 T)/5
Multiply both sides by 30:
(30 (T + 780))/6 = (30×3 T)/5
5 (T + 780) = (30×3 T)/5
5 (T + 780) = 6×3 T
5 (T + 780) = 18 T
Expand out terms of the left hand side:
5 T + 3900 = 18 T
-13 T = -3900
T = 300 Gallons when the tank is full.

Thank you so much, CPhill!!!!!!!!!!!

Thanks so much!

Thanks.

Look at the graph here, AT : https://www.desmos.com/calculator/1q5zvkdasv

domain  = all reals

range = [ 1, infinity )

No x intercepts

y intercept  = (0, 1)

thanks

A

mean=\(\frac{A+B+C}{3}\)

For this to be an intiger, A+B+C must be a multiple of 3.

To get the largest possible mean, the numbers would have to be 47, 48 and 49 are A, B and C, respectivly.

47+48+49 = 144 which is a multiple of 3 so I don't need to try anything else (although the sum of any set of 3 consecutive intigers would be a multiple of 3).

144/3 = \(\boxed{48}\) is the greatest possible mean.