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Good job, Guest!!!

I think we'll  take your word for it!!!

LOL!!!!

YASSSSS I think I did it an wrong way though...I went like 4 numbers, 3 odds...

3odds/4numbers.... lol

The number of possible arrangements of the digits  is 4!  = 24

Let's look at those which form even numbers.....this occurs when the "2"  appears at the end of a number

So....in that case.....the other digits can be arranged in 3!  =  6 ways

So.....there are 6 even numbers and 18 odd

So

18 / 24  =   3 / 4     and you are correct!!!!

I honestly got -162.something, then retried and got 56... so I came here... And I was wrong both counts... Nobody on the internet agrees with me...

You are RIGHT! THANK YOU!

I wrote a short code and listed all 3-digit combinations and they came out to =7,260 !!. Here is the code:

a=1; b=1;d=1;p=0;c=a + b + d; if(c==418, goto6, goto8);p=p+1;printp," - ",c, a, b, d; a++;if(a<180, goto4, 0);a=1;b++;if(b<180, goto4, 0);a=1;b=2;d++;if(d<180, goto4,0)

P.S. I hope that he/she doesn't want them ALL listed!. 

I believe that there are many such three integer patterns.....for example.... 

64, 176,178   [sum = 418, all are < 180   and all are unique ]

or

66, 174, 178  

A computer program could probably  be designed to generate all the possibilities

Maybe $105?    I had to loOk this one up also....but the example I found may be incorrect...

362(.99) -(25700-362)(.01) = $ 105

300 (1.03)^4 = $337.65     assuming annual compounding.

If I understand the question.....look at the following pattern :

1, 2, 4, 8, 16  = not sweet

2 ,4,8,16  = not sweet

3, 6,12, 24,(48,36,24)....the (48,36,24) repeats   = sweet

4,8,16 = not sweet

5,10,20,40,28,16 = not sweet

6, 12, 24, (48,36, 24) = sweet

7, 14, 28, 16   = not sweet

8, 16   = not sweet

9, 18, 36, 24, (48, 36, 24)  = sweet

10, 20, 40, 28, 16  =  not sweet

11, 22, 44, 32, 20, 40, 28, 16  = not sweet

12,24,(48,36,24) = sweet

It appears that the multiples of 3 will only generate  "sweet" numbers

There will  be     integer ( 50/3)   =    16  such "sweet" numbers from 1 - 50

Yes, 418 can be split into a group of three numbers.

418 can be split into 138 + 139 + 141.

418/3 = 139.333333333 and that keeps gong on forever. So the numbers must be around that point somewhere.

138+139+140= 417. We are one number off from 418. So, logically, if we added 1 to one of the numbers, we would get 418.

Since you said all the numbers must be different, we can't add the one to 138 or 139, since then two numbers would be the same.

But, we could add the one two 140, since there are no other numbers in that equation that equal to "141."

So, now our equation is 138+139+141= 418.

Hope this helps!

I stole your trademark... LOL

No prob.....!!!

Thank You, You are correct.

P(< 15 from Box A)  = (14/20)  =   7/10      (1)

P(even or > 25 from Box B)   = 

P(even from Box B) + P(>25 from Box B)  - P(even and > 25 from Box B)  =

(10/20) + (5/20) - (3/20)  = 12/20  = 3/5     (2)

So.....the probability of  (1) and (2)   =   7/10  *  3/5  =    21 /  50

 and guest, this is my face toward all of you now because of your negative influence. It seems to me that guests only make mean/cruel comments here now...

Ok, Why would I make the posts? And even if I did, it would change it into my username anyway. And secondly, we both attend the same school. Third, why would I want her in my bed? We are friends... but eww. Stop faking. And Why would I make the rude posts? Those were just evil... I was playing Roblox with her- I wasn't typing on web2.0calc... I mean, I wouldn't spend my life here- I only check up on this every 6 hours or so, and leave the tab open. Guest, that post was offensive.

I posted in the wrong spot 

for

(Thats Better

) 

Lol; Why so rude about that m

an thats why Guest are down voted!!!!! 

Always rude only some are nice! 

Thank you very much as well!

Thank you for your work!

Thank you for you thorough steps, I really understand now!