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the sticky topics sidebar is also pretty helpful

Thank you for the modulus lesson!

or you can socialize, but mark it off-topic if you are posting it as a question.

Welcome Hexxel, you can help other ppl or get helped!

you have signed up to a math forum.

in other words, welcome (=^ェ^=)！

Hey, Can you avoid posting the same question pasted again and again? 

? Is that a question?

The probability of getting a tails on the tenth toss is 1/2. Previous results do not have any effect on future tosses. For the tenth toss, the odds are 1 out of 2 possible choices. The answer is significantly different if you ask what are the odds of tossing heads 10 times in a row.

the answer is A.

16.67

20000  / 1200   =    ????

Correct   !!!!

Arizona ?

(5.5)^3  - (4.5)^3

We have a difference of cubes.........we can simplify this as follows

(5.5 - 4.5) ( 5.5^2   + 5.5*4.5  + 4.5^2 )   =

( 1)  ( 30.25  + 24.75  + 20.25)  =

(1)  (  75.25)   =

75.25

Average  =

Sum of Values

________________

Number of Values

Each toss of the coin is independent of any other toss......the next toss has a  1/2  probability of being a head or tails

Mississippi has 4

Which state has  8   ???

Melody the answer is right above yours

y=4x-8 meets the x axis at point A 

, In other words Point A intersects the x axis, (Draw the graph and you will find that A=2) or simply solve for it setting y=0 

4x-8=0

4x=8

x=2(Intersection)

Second part of the question find the equation of the line with gradient 3 that passes through point A,

Gradient is slope.

y=mx+c

m is the slope

In this equation it is 4x (Slope is 4)

So you want a line that intersect the x axis at the same point (A) at 2. but with slope=3

simply,

y=3x-6 

Area of sector   =   (1/2)r^2 * theta

Perimeter of sector   =  2r + r *theta =   r [ 2 + theta]

Where theta is the measure of the sector's central angle in radians

So

49  =  (1/2)r^2 theta   ⇒  49 / [(1/2) r^2]   =  theta     (1)

28  =  r [ 2 + theta]      (2)

Subbing (1)  into (2)   we have that

28  = r [ 2 +  49 / [(1/2) r^2] ]       simplify

28 =  2r + 98/r

14  = r + 49/r     multiply through by r

14r  = r^2 + 49

r^2  - 14r + 49  = 0

(r - 7)^2  =  0

r  - 7  =  0

r  = 7

So....the arc length of the sector    =

28 - 2(7)  =

28  - 14  =

14 cm

(x^5+x^4+x+10)-(x^5+2x^4-x^3+12)

  (x^5 + x^4  + 0x^3  +  0x^2  + x  + 10)

- (x^5 + 2x^4 - x^3                       +  12)

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  x^5 + x^4  + 0x^3  +  0x^2  + x  + 10

- x^5 - 2x^4  + x^3                       -  12

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        -x^4 + x^3                   + x - 2