All Answers 358516 Answers

You havent given TakahiroMaeda  anypoints??

anyways , for a tip , u could use the on-site calc as well for this , as much as i know it still works on such problems!

General formula for what? Need more information.

haha ty :)

19 is the answer.

So we would solve this like ( just edited the answer and placed the bracktes missing)

$$\frac{((2*2)+2-2)}{2}$$   (here first we will solve the first part or the numerator step by step in which we will first multiply , then add and then at last subtract)

$$=\frac{(4+2-2)}{2}$$       $$(now $ simply add then subtract )$$

$$=\frac{4}{2}$$               $$($and now out here we will simply divide which will then give us our answer)$$

$$=2$$   $$ANSWER$$

I hope u've understood by now but if not then pls be free to ask!

hope this  helps!

Aziz's answer is only  correct if the missing bracket is put at the very beginning. 

You have an odd number of brackets 

This polynomial only has one real root: (x - 0.3127) --> x = 0.3127.

((2*2)+2-2)/2

PEMDAS: ((2*2)+2-2)/2 --> 4 + 2 - 2 / 2 --> 6 -2 / 2 --> 4 / 2 = 2.

thank you both ! 

Hint....m<ACD  = 1/2 of its intercepted arc - since it's an inscribed angle.

And the arc that it intercepts is minor arc AD.

Does that help??

(The fact that AB and CD are parallel would only be useful info if we were trying to find m<BAC)

Methinks there is no positive integer solution to this! See below:

3.  If there were a net force on the plane it would accelerate (or decelerate) - i.e. its speed would be changing - but the plane is travelling at constant speed so there must be zero net force on it.

4.  Think of light going from, say, glass to air.  Total internal reflection can occur.  The refractive index of glass is greater than that of air.

5.  273K (approx).

6.  This is already done in the picture!

WolframAlpha gets a slightly different result from Melody's answer...I suspect the reason is in the way that WA is interpreting the multiple divisions of the two functions outside the brackets....

(The only change I made to the original problem was to subtract .2336 from both sides....)

Whatever.....I think the point here is that this one would be a tough one to evaluate by hand.......Based on the original form of the problem, it would be difficult to intuit how many "real' and/or "non-real" solutions there might be......

So we have triangle ABC with AB = 45, AC = 38, and an included angle BAC = (90 - 62) = 28°

And we're looking for BC. We can use the Law of Cosines for this.

BC² = AB² + AC² - 2(AB)(AC)cos28°

BC² = (45)² + (38)² - 2(45)(38)cos28°

BC² = 449.31923242222   ...and taking the square root, we have

BC ≈ 21.2 km

example:

$${\mathtt{2}}{i}{\mathtt{\,\times\,}}{\mathtt{2}}{i} = -{\mathtt{4}}$$

Either this is some branch of mathematics that is above me, or this post isn't detailed enough.

Can you give an example of a complex number?

Thanks. That and kahn acadamy helped a bit. It is integration always to get a function right? 

Melody the reason to integrate is 2 fold as far as i saw on kahn acadamy. First we want an equation of a function as a rezult zo have to undo the differentiation that has occured. Sec9ndly to apply integration is applying small change in dp and dt resprctively as inthe above example and alans explaination. Thanks guys.

Following cphills reply. The reaso  is 3 out sidr the squareroot sign is squared when it is put back in side. This us the opposite when taking the 3 out in surds. Then any two sqyare roots that are the same such as root 2 and root 2 when multiplied become 2. Hope this helps with the post and where the information was provided from. Lastly he has just done this to get whole numbers for the simplest solution. Stu

So we will write this as

negative 44 means -44 and nehgative 8 means -8  and so we will place then according to the question and subtract

we will place them in brackets

(-44) - ( -8)  ( as two negatives give as postive so minus , and minus 8 will become -44 + 8 )

= -44 + 8 ( and now we will simply subtract them both)

= -36   ANSWER

i hope uve understood by now!

hope this helps!

Mon 11/8/14

Interesting little 3D/algebra question.

@@ End of Day Wrap :      Sun 10/8/14      Sydney, Australia     Time 7:10  pm  

Hi all,

It was a very quiet Sat/Sun today.  There were a few good answers given by AzizHusain, Alan and CPhill. Thanks for those. 

Here are a couple of interest threads.

* Complicated 'quadratic' equation - extension question, for interest only.

Thanks Alan,

I'll spend more time in it. 

Thanks Alan.