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I already answered this your lazy git.

You are very welcome.

There is a lot that can be learned from the way I have drawn the pic. See if you can get as much as possible out of it.  

N mod 2 =1, N mod 3 =2, N mod 4 =3, N mod 5 = 4, N mod 6 =5, N mod 7 =0, solve for N
LCM(2,3,4,5,6,7) = 420
Using Chinese Remainder Theorem + Modular Multiplicative Inverse, we get:
N =119. The least number of eggs in the basket.
The full solution is:
420m + 119, where m=0, 1, 2, 3..........etc.

I believe the vertex will be shifted 3 units to the right       to    4, -2

s = seniors                        revenue from = $ 109 s

41-s = regular                   revenue from = $ 113 (41-s)     summed = $ 4561

109 s        +      113 (41-s)           =    4561        solve for  's' the number of senior tix

12/30  white sock first *   18/29    black c**k next       +      18/30 black sock fist  *  12/29  white sock next

216/870   +   216/870   =  432/870 = 72/145     (someone verify this ? )

Good answer...

.but you probably do not know that you cannot have the same numbers repeated in your choice of numbers....

56  *   55  *  54 * 53  *  52      *    46   = ...............

I don't know if the fact that the lottery is in 12 states affects the problem, so I'm just going to assume that it does not. 

I'll also assume that the 5 numbers could be equal. If that is so, then the probability for 5 numbers between 1 and 56 is \(56^5\), times the probability for the single number between 1 and 46 which is 46. Multiplying gives \(56^5 \cdot 46.\)

Convert 1/4 into 2/8

then add

answer is 3

3

Lets say the total is 48 units of work

Pipe A can do 6 units of work per hour

A and B combined can do 8 units of work per hour

B can then do 2 units of work per hour 

38/2 = 24

24 hours

y=2x+1

mb=2*1=2

Consider a regular 23-gon. How many diagonals does the regular polygon have?

It has to be a fraction though,

g = 2 r

r

2r-42  = 1/2 r

3/2 r = 42

r = 28       g = 2r = 56         56 + 28 = number of pencils originally       56 + 28 - 42 = pencils after he lost 42

Answered in your post yesterday.....did you even look at it?   ( the ONLY difference being it is +4  instead of +3 at the end in this Q !!)

https://web2.0calc.com/questions/please-help_97798

total are of circle =  pi r^2  =  64 pi

The fraction of 2pi radians (a whole circle) that is 5pi/4    is     5 pi/4   /   2 pi =  5/8

5 / 8      x    64 pi = ........ ft²

From -2     to 2   is + 4 units of change      f(x)   changes from  25 to 9   a change of -16

avg rate of change/unit    =    -16/4  =  -4 /unit

An triangle ABC, AB=13, AC=14 and  BC=15. Let I be the incenter. The incircle of triangle ABC  touches sides BC, AB, and AC at D, E, and F, respectively. Find the area of quadrilateral AEIF.

The graph of the paraobla is y = x^2 + 6x + 5, so a*b*c = 1*6*5 = 30.

Hello guest!

There are a total of 18 students. Of the 18 students, there are \(\binom{18}{3}=816\) ways to choose three students. 

Of the 6 boys, there are \(\binom{6}{3}=20\) ways to choose the boys. 

Therefore, the total probability is 20/816 = 5/204

I hope this helped, 

Gavin. 

Hello Guest!

If we set the number of three point baskets he made as x, we can write the following equation for the total amount of points he scored. 

22 = 2 * (4x) + 3 * x 

22 = 8x + 3x

22 = 11x

2 = x

x = 2

Since x = 2, we know he scored 2 three pointers. 

I hope this helped, 

Gavin. 

Thank you for your help 

The total number of paintings is given by:  x(x-2) + x + 2x + 8 + 10 = 60  or, simplifying, x² +x - 42 = 0 

 This can be factored as (x+7)(x-6) = 0, so the only positive solution is x = 6.

However, since you are given the fact that x is from the 20th century the probability it is British is x/[x(x-2)] = 1/(x-2) = 1/4