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Circumference = pi d

A   diameter = 24 feet

B   diameter = 7.5 m = 7.5 m / .305 m/ft = 25 ft       B is larger because diameter is larger....I'll let you calculate the circumferences with the equation in red

The remainder will, in general, be a polynomial of order less than that of the divisor (otherwise it would still be divisible by the divisor). So

remainder = u*x² + v*x + w 

The non-remainder part vanishes when x=0, 1 or 2, so 

f(0) = 4 = u*0 +v*0 + w, or w = 4

f(1) = 5 = u*1 + v*1 + 4, or u + v = 1

f(2) = 10 = u*4 + v*2 + 4 or 4u + 2v = 6

From these last two equations we get u = 2 and v = -1

Remainder = 2x² - x + 4

Thank you so much!

Q I     0 -90

Q 2    90- 180

Q 3   180 - 270

Q 4   270 - 360

- 230 is the same as 130^o

y = mx + b        m = slope =  ( 1 - -1)/(0 - - 5)   = 2 / 5 

y = 2/5 x + b     sub in one of the points to find 'b'

  You have the center....you need to find the radius...this will be the distance from the center to the point given

d = sqrt ( (-11 - -15)^2  + (11-7)^2 )   = sqrt 32

Then standard form is       (x-h)^2 + (y-k)^2 = r^2

                                          (x+11)^2 + (y-11)^2 = 32

Here is a pic:

  https://www.desmos.com/calculator/pqssr0xmvj

I would like to see someone knowledgable do this one too.   

2/7 + 1/14  

We need to determine a common denominator for each term       2/7 + 1/14

In this usage, the word "common" means they're the same 

By observation we see that one common denominator is 14 

So multiply 2/7 by 2/2 to obtain 4/14                                             4/14 + 1/14 

Now the addition is simple                                                             4/14 + 1/14  =  5/14 

_.

ok  

I can see exactly where you're coming from. I believe that this issue so systemic throughout my facilty that most (including myself until now) do not know we're writing it incorrectly. I can see your way as correct.

I guess we've essentially made our own language while being oblivious to it.

You:

"interesting. I see how you're getting confused.

------

I hope that makes sense"

My response:

You may find it 'interesting' but I do not think it is me who is confused.

And no, what you have written does not make sense.

I'll second Alan's sentiment!

The volume of the real statue is Vreal = 672.28*10³g/(2g/cm³) = 336.14*10³ cm³.

Volumes scale as the cube of linear dimensions, so the scale factor is (15cm/105cm)³ = (1/7)³.

Hence the model has a volume of 336.14*10³*(1/7)³ cm³.

You can do the number crunching.

Thanks for your help guys. I appreciate the insight into mathmatical correctness.

This is a typical example of how engineers butcher math lol.

You don't say what the units of 281.25 are.  Presumably they are kN.m. (Edited again!)

This means that 281.25 kN.m = 281.25*10⁶ N.mm  or it could be written as 281.25*10³ N.m

In terms of your original question you could have: 1000N*3m = 3000N.m or 3*10³ N.m or 3 kN.m  but you should never see 10^-3 appear anywhere here!

here's a good example from my lecturer. I just happen to have it open now.

"This is how my teaching team have been writing their expressions over the years "

Your teaching team needs to be shot!!!

To relate to the percentage example above,

"*100%"

I guess it could be written as "*10^-3kN"

interesting. I see how you're getting confused.

This is how my teaching team have been writing their expressions over the years the

*10^-3 is meant to signify the coversion from 3000N to 3kN. It's not suppose to be a part of the mathmatical problem.

I hope that makes sence

No, I think you have made it worse.  it is the minus index that is wrong.

1000=10^+3

1000N* 3m *10^-3 =3000Nm/1000 = 3Nm  NOT   3kNm

Sorry melody. I meant 1000N ://. I've amended the original post.

Hi vest4R

The first one is confusing me.   where did 10^-3 come from?  

1000N*3m = 3000Nm   (3kNm which is your notation but personally I don't like it much.)

However,

10^-3 = 0.001  it is not 1000

10N* 3m *10^-3 = 30Nm/1000 = 0.03Nm  NOT    3000Nm   and not     3kNm

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The second one is fine. 

1/4 is the same as 25%

∑[ 1 / ( n^3 + 3 n^2 + 2 n), n, 1, 99] =5049 / 20200

In triangle ABC, AB=13, AC=14 and  BC=15. Let I be the incenter. The incircle of triangle ABC  touches sides BC, AB, and AC at D, E, and F, respectively. Find the area of quadrilateral AEIF.

AB = 13        AC = 14       BC = 15

I     c     I       I      b     I      I     a     I

Semiperimeter    s = ( a + b + c )/2 = 21

Triangle (ABC) area is:    A = sqrt [ s (s-a)(s-b)(s-c)]  = 84 u²

Radius   r = A / s   = 4

Angle   BAC =>           cos(∠A) = ( b² + c² - a² ) / 2bc   = 67.38°

AE = AF  = r / tan (∠A/2)  = 6

Area of quadrilateral  AEIF  = AF * r  = 24 u²