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With the information given I can't find r 

7 - 2 = 5

You can also use a calculator for this

7-2=5

Same dude here... almost done

I'll help!

Give me actual prob

Do you mind telling me what kind of problem?

1.  The  equation of the line can be  found  as follows :

y = (2/3) ( x + 18)  - 12

To find  the  x intercept, let  y  =  0  ......so we have....

0  = (2/3)(x + 18)  - 12         add  12 to both sides

12  = (2/3) ( x + 18)      multiply both sides  by (3/2)

18  = x + 18         subtract  18 from both sides

0  = x    ⇒  the   x intercept

depends, whats it about, then i might do it

i'll help as well, mode and median is easy

thank you

I'll help... but bro whats the problems?

To solve  (3 - z) / (z + 1) >= 1

you need to consider two situations:

1) when z + 1 is positive, and

2) when z + 1 is negative.

For situation 1:  z + 1 > 0   --->   z > -1

Solving by multiplying both sides by z + 1   --->   3 - z  >= z + 1   --->   2 >= 2z   --->   z <= 1

But, we must combine that with the restriction that z > -1 to get:  -1 < z <= 1

Now, for the situation when z + 1 is negative   --->   z + 1 < 0   --->   z < -1

Multiplying both sides by z + 1 (since z + 1 is negative, we must change the direction of the inequality)

--->   3 -z <= z + 1   --->   2 <= 2z   --->   1 <= z   --->   z >= 1   This is impossible, so we must reject this possibility!

We have to consider both possibilities because we have to change the direction of the inequality.

Let A = (7,-4), B = (-3,-4), and C = (6,-7).

Then, consider the two segments AB and BC.

The perpendicular bisectors of these two segments meet at the center of the circle.

1) Find the midpoint of AB and the slope of AB.

    Using the midpoint that you just found and the negative reciprocal of the slope that you just found,

    find the equation of the line which is the perpendicular bisector of AB.

2) Repeat the steps of part 1 to find the perpendicular bisector of BC.

3) Use those two equations to find the point where they intersect. 

    This will be the center of the circle.

4) To find the radius of the circle, use the distance formula for the center of the circle and one of the 

    three given points.

5) You now have the center and the radius; use these values to find the equation of the circle.

Once again, formatting please. The question is unreadable as is.

Could you please repost your question with proper formatting? The question is unreadable as is(which is sometimes the case when problems are copy pasted from other sites onto web2.0)

Let's look at the two points we're given: 

we can find the slope of the line by taking the difference of the respective ys, and dividing by the difference between the respective x's(rise over run). This gives us a slope of : 1 - (-5) / 6 - (-3), or (1+5) / (6+3), which is equal to 6/9 or 2/3. 

With this, we can write the equation of the line as:

y = 2/3x + b. Now, we just have to solve for b, which we can find by just plugging in a point on that line. Let's use the point (6,1).

Plugging in (6,1) for the x and y values respectively, we get:

1 = 6 * 2/3 + b, or

1 = 4 + b. Subtracting 4 on both sides, we get:

-3 = b

This then gives us the equation y = 2/3x - 3, but since the question asks for standard form which is Ax + by + c = 0, we can rewrite the equation as:

3y = 2x - 9 from multiplying the equation by 3.

Then, rearranging to get our desired form, we get :

2x - 3y - 9 = 0. Since the question asks for A + B + C, we get 2 + (-3) + (-9), which is equal to 2-12, or -10

Multiply both sides by  z+1 to get

(BUT there is another consideration.....see Geno's answer below)

your thinking is in the right direction. Are you considering the cases where the Ace isn't the first one drawn?(becaues I'm assuming the order does matter in which you draw them). As such, I would try multipliying by the number of ways that you can draw the hand given(in other words, an Ace, a 2, and a 3)

well we know that the equation of a line parallel to the given line must retain the same slope. As such, the slope has to be 3 as well. We can then write part of the equation of the line as 

y = 3x + b

Now we just solve for b, by plugging in the point (-4, 1) which we know the line passes through. With this point, we get 1 = -12 + b. Adding 12 on both sides, we get 13 = b.

We then get the equation:

y = 3x + 13

Let's first define the point P as (x,x) since the slope of line OP is 1, meaning the y = x. Next, realize that the distance between P to the origin is equal to the distance Q to the origin. The distance can be defined as sqrt(x^2 + x^2) by pythagorean theorem, giving us x(sqrt2) as the distance to the origin. That means that the distance of line segment OQ is x(sqrt2), and since the slope is 7, the point can be represented as (7y, y). With pythagorean theorem, we get 49y^2 + y^2 = 2x^2, which simplifies to 25y^2 = x^2. Square rooting both sides gives us 5y = x. Now, we have the two points P and Q in terms of y. P is equivalent to (5y, 5y), and Q is equivalent to (7y, y). Now we can find the slope of line segment pq with the formula (delta y / delta x), which is just equal to (y-5y) / (7y-5y), simplifing to -4y / 2y, which gives us a slope of -2

Realize that h(7) is equal to 5. Look at the graph, and we see that indeed, if we count out 7 spots from the origin xwise, the y value that corresponds is 5. As such, if we want to compute h(h(7)), that's equivalent to h(5). We repeat the process for h(5). We count out 5 spots, and we see that the y value that corresponds with 5 is -1, giving us our answer.

Count over to x = 7     count up to where you intersect the red graph   this is   h(7)    and it equals 5

   now count over x = 5    and count to the red line     -1                    h h(7) = -1

B unit rate  =  40.5 m / 1.25 gal  = 32.4 m/g        B can go   32.4 miles on one gallon

R unit rate   =  27.2m/ (4/5gal) =   34 m/ gal       R cn go 34 miles on one gallon