You seem to be missing some numbers in your post!

Slope is equivalent to rise over run, or the change in y / change in x between two given (distinct) points on the line\(\). Let's look at the x and y intercepts which are 10 and -6 respectively. Over a distance of 10 units, the graph rises by 6, meaning that rise / run = 6/10 = a slope of 3/5

Plan:

 - Convert it into the y = mx + b form. m is the slope

 - The line that is parrelel to the given line has the same slope.

Converting:

(1.) 2x + 4y = -17

(2.) 4y = -2x - 17

(3.) y = -(1/2)x - 17/4

[Now it's up to you to find the slope.]

Please make your question more clear. 

- The height is 6, but is the circle's area 4, is the circle's radius 4, or is the circle's surface area 4???

- Is it a right circular cone?

This is not the best way to solve, but it is the best way (in my opinion) to understand it.

Plan:

For these problems, we can make it easier by PRETENDING that the total number of people is 1000.

Solve:

Since the ratio of males to females is 3 : 2. Let us calculate the exact number of males to females using the information we have in our plan.

3 + 2 = 5

5x = 1000

x = 200

20 * 3 = 600 males

20 * 2 = 400 females

42% of males = 0.42 * 600 = 252 males

64% of females = 0.64 * 400 = 256 females

Add them up 508 people who voted to re-elect the senator.

Out of the 1000 people, 508 of them did. So the overall percent is 508/1000 = 0.508, or 50.8%

I unfortunately do not have a Chegg account with a paid subscription. 

Just a picture for those who want to see:

Take a look at this:

Question 3:

(I drew this)

Consider:

Angle APO = 26 and the right angles formed by tangent and radii lines

By the Two-Tangent theorem, BP = PA

By a serious of proofs, we know that triangles BPO and APO are congruent by SSS.

Solve:

Because of CPCTC, we know that BPO is congruent to APO and is therefore also 26 degrees.

We solve for BOP and AOP

BOP = 180 - 26 - 90 = 64

AOP = 180 - 26 - 90 = 64

BOA = 64 + 64

Minor arc AB = \(\boxed{\text{Now you can do it!}}\)

Question 2:

Draw:

We draw TO, OU, and OA so that they meet at the center as radii.

Plan with what you know:

Since angle QTA = 41 and angle RUA = 63, we can use that information to find angle TOU.

TO, OA, and OU are all congruent as they are radii. Because of this, isosceles triangles TOA and UOA are formed.

Solving:

PUA = 180 - RUA = 117

PTA = 180 - QTA = 139

OUA = PUA - 90 = 27

OTA = PTA - 90 = 49

UOA = 180 - 2(OUA) = 126

TOA = 180 - 2(OTA) = 82

TOU = 360 - (UOA + TOA) = 152

QPR = 360 - 90 - 90 - TOU = \(\boxed{\text{Now you do the rest!}}\)

Shouldn't be that hard, considering that you read my solution.

Have a nice break!

Thank you! I am much more informed now. :)

Check this problem out here:

Question 1:

(I drew this)

AD = 10 - 7 = 3

Through a series of proofs, we know that ADB is similar to BEC by AA.

We set up a proportion.

1. \(\frac{AD}{AB}=\frac{BE}{BC}\)

Subsitute in known values.

2. \(\frac{3}{17}=\frac{7}{BC}\)

Can you solve for BC?

The following hints are not the best way to do it, but the best way to understand it.

For the first problem:

Consider:

Perimeter = 2L + 2W

Set Up:

"The length of a rectangle is five meters less than twice the width​"

L = 2W - 5

Equation: 44 = 2L + 2W

Now solve!

Using this method, you can solve the rest.

This is just to find the polynomial. I believe you need to use Pascal Triangle to find the rest.

Consider:

Standard form:

ax² + bx + c = 0

Use your information:

(1)    a(-4)² + b(-4) + c = -22

(2)    a(-1)² + b(-1) + c = 2

(3)    a(2)² + b(2) + c = -1

Simplify:

(1)    16a -4b + c = -22

(2)    a - b + c = 2

(3)    4a + 2b + c = -1

These equations are solvable because there are 3 variables with 3 equations.

Solving:

(1) - (2) = 15a -3b = -24

(2) - (3) = -3a - 3b = 3

Subtract the two resulting equations

18a = -27

a = (-3/2)

From here, it is basic algebra to find the rest of the variables.
a=-(3/2) b=(1/2), c=4

Our quadratic polynomial is:

\(-\frac{3}{2}x^2+\frac{1}{2}x+4=0\)

Question asked and answered here: https://web2.0calc.com/questions/i-m-really-stumped-polynomials

sorry about that can you check this link please

https://free-picload.com/image/qtzdrA