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Call the center of the circle C. Since the diameters PQ and PR are perpendicular, we know that sectors PCR and SCQ are quarters of the circle. The area of the circle is 16 pi, so 1/4 of that is 4 pi and since there are two quarter sectors, that means that the area of them both is 4 pi * 2= 8pi. The right triangle PCS and RCQ have legs of 4. The area of the triangls are (4 * 4)/2= 8, since there are 2 triangles, the total area is 16. Combine this area with the sectors to get 8 pi + 16 as your answer.

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Calling the center of the circle "C".

The area of the whole circle is:  A  =  pi·4²  =  16pi.

The area of the sector PCR is one-fourth the whole circle --->  ¼·16pi  =  4pi.

Similarly, the area of the sector SCQ is 4 pi.

To find the area of the shaded triangular area in sector PCS:

  this is a right triangle whose side are each 4:  A  =  ½·4·4  =  8.

Similarly, the area of the shaded trianglular area in sector RCQ is 8.

We need to add these four areas together:  4pi + 4pi + 8 + 8.

The water level goes up .4 feet for every .5 hours according to the chart. This also means it goes up .8 feet every hour. Using this as our slope or rate of change, we find that in 0 hours the water level was 18.7-.8= 17.9 feet. This is the original water level. With this information, the equation we get is 0.8t+17.9=w(t).

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The slope is 1, the y-intercept is 1, so the equation of the line is y = 1x + 1, or just y = x + 1.

Since the line is dashed, it will either be y > x + 1 or y < x + 1.

To find out which one, let's test a point from the shaded area. I'm going to pick the point (1, 3).

Substituting 1 for x, and 3 for y, we see that 3 > 1 + 1 is true; so we should pick y > x + 1.

Had we tested y < x + 1, we would have gotton 3 < 1 + 1, which is false; this would tell us not to

choose this possible answer.

We have chosen y > x + 1; now, we need to put it into correct form.

Starting with:  y > x + 1, we can get:  -x + y - 1 > 0.

It doenst say which brackets to use

Did you use coordinate geometry?

If you draw a Venn diagram , you will find 10 students play both sports     out of 28 students     10/28 =   5/14

John's farm silo is a right cylinder that is 35 feet high. Both the top and bottom base have a diameter of 22 feet. What is the approximate surface area of the metal used to make the silo? 

The trains are separating at  85 + 95 = 180 m/hr

252 miles/ 180 m/hr = 1.4 hours

The two circular ends will each have the area of the circle    2   x  pi r^2      ft₂            r = 11 ft

the cylindrical sidewall will have an area of  pi d h    ft²         d = 22 ft     h = 35 ft       plug and chug !

535 miles  - 190 miles - 106 miles =  .......   miles on Sunday

L = 12 + 2H

2L + 2H = 264

2(12+2H) + 2H = 264

24 + 6H = 264

H = 40    then L = 12 + 2H = 92

The mildly embarrassing fact is that I solved it with complicated mathematics.

I got the answer 0 and though I had made a mistake.

I finally looked at it properly and the penny dropped.    Doh !!!

Two trains leave the station at the same time, one heading west and the other east. The westbound train travels at 85 miles per hour. The eastbound train travels at 95 miles per hour. How long will it take for the two trains to be 252 miles apart? Do not do any rounding.

I have no idea LOL

Ummmm... this is an Amazon Interview Question? I didn't know they did this before hiring a worker. Or am I just mis-interpeting this.

Yeah my reasoning sucks...

Thank you!

g(x)  =  3x + 5     h(x)  =  4x

(g · h)(x)  =  g(x) · h(x)  =  (3x + 5) · (4x)  =  12x² + 20x

(g + h)(x)  =  g(x) + h(x)  =  (3x + 5) + (4x)  =  7x + 5

(g - h)(x)  =  g(x) - h(x)  =  (3x + 5) - (4x)  =  -x + 5

     --->   (g - h)(3)  =  -3 + 5  =  2

If  |ax + b|  =  c|ax + b|  either  c = 1  or  both  c = 0  and  ax + b = 0.

If  c = 1:  and c|ax + b|  =  c   --->   |ax + b|  =  1

then  either  ax + b  =  1   --->   ax  =  1 - b   --->   x  =  (1 - b)/a

         or    -(ax + b)  =  1   ---?   -ax - b  =  1   --->   -ax  =  1 + b   --->   x  =  (1 + b)/-a   --->   -(1 + b)/a

If both  c = 0  and  ax + b = 0:

then  ax =  -b   --->   x  =  -b/a

Here's the answer for part (a):

See if you can use the same technique for part (b).