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Start by drawing a Venn diagram (btw I know your in AOPs class because I did it too)

If you are stuck use the message board in AOPs

Trig

So, we have a right triangle. 35 feet is the measure of the vertical leg, and 75 ft is the measure of the other leg.

The tangent of the angle of elevation would be \(\frac{35}{75}\) . So, tan(x) = 35/75 = 7/15, and 7/15 = arctan(x) + pi with the reference angle, that simplifies to something like 25.0165 degrees + pi with the R.A. I am not the best at this stuff :(

So, I'm just going to randomly calculate the hypotenuse ¯\_(ツ)_/¯

Using the Pythagorean Theorem, we know that \(35^2 \cdot 75^2 = \text{hypotenuse}^2 = 6850\)

Therefore, the hypotenuse of the triangle is the square root of 6850. I just found this to complete the triangle, it's unnecessary :D

Hehe Lol!

Better check that arc tan calc !    

First, let's form a right triangle with two legs of 75, with 35 being the height of the building, and 75 being the distance that you are standing from the building. Next, we know that the tangent of our angle is opposite/adjacent, which means it is equivalent to:

35 / 75 = 7 / 15

Finally, to get our desired angle, we take the arctan(7/15), which will give us our desired angle. Plugging it into a calculator, we get an angle of:

62.1818607 degrees, which rounds out to 62.2 degrees 

No probs!

Yess

OK its right btw thanks!

Oops just a Letex error 

its suppost to be..

Dividing both sides by 9 gives \(x=\frac{24}{9}=\frac{8}{3}=\boxed{2\frac{2}{3}}\)

How did you know the mixed number is 24/9? I don't think some images are showing up on my computer, I couldn't see it D:

Lol IDK why the $ though, ehhh its fine no difference 

6 * 1/x = x

6/x = x

6 = x²

6 = sqrt(6)

Of course, this is assuming 6 times the reciprocal of a number is the number itself. What's in the gap? :D

Using Algebra...

Letting x be the desired number, we have \($\frac{6}{x}=\frac{9}{4}$\). Multiplying both sides by x and by 4 gives 24 = 9x . Dividing both sides by 9 gives \($x=\frac{24}{9}=\frac{8}{3}=\boxed{2\frac{2}{3}}$ \).

Thanks, but do you know what that would be in radians in terms of pi?

atan(sqrt(2)) = 54.735610317245^o  = .9553 R        =  .304086 pi

I think not...

Oh ok thx (sry I'm learning latex rn)

I agree

True, but from exactly a year ago!

Coincidence? o _ O

BTW, the web2.0calc LaTeX/TeXer does not need dollar signs :D

You already asked this question, is more explanation needed? :D

Please do not discuss this problem!  This is an active homework problem.

 I realize that homework may be challenging. If you wish to receive some help from the staff or other students, I encourage you to use the resources that the online classes provide, such as the Message Board.  Thanks.

TY LuckyDucky!

Again another repost

https://web2.0calc.com/questions/homework-problem-and-need-help#r1

∫ 8 e^{x+ 1}  dx  =

8 ∫ e^{x + 1}  dx  =

8 *  ( derivative  of x + 1) * e^x+1  +  C   =

8 * ( 1) * e^x+1  +  C  =

8e^x+1  + C