In the sequence 1, 5, 4, 1, 3, 2, ..., every term is equal to the absolute value of the difference of the previous two terms. Find the 1994th term.
I don't know where you got that 5 but let's continue the sequence: 1, 5, 4, 1, 3, 2, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 0
It starts repeating 110 at the 7th number so there are going to be (1994 – 6) / 3 = 662 & 2/3 groups, so it will be 2/3 of the way through the 663rd group, and 2/3 of the way through any of those groups is a 1. I'm confident my reasoning is solid so I'm going with a 1.
.