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x= side length.  
  X/6 time for one side at 6 f/s

  x/5 time for one side at 5f/s

4x / (x/6.  + x/6.  +x/6.  + x /5)

4x/(x/2+x/5)

4x/(7x/10)

40/7=40/7 = 5.7142857142857143 f/sec avg

So

even * odd = even

odd*odd = odd

even*even.= even

even+odd = odd

even+even = even

odd + odd = even

So for subsets containing 2 we must have 2 odds.Thus all odds work.

6odds-

6c2 = 15

Trios: We must have all odds, but odd+odd+ odd = odd.so thus there are no possibilities for subsets with odd amounts.

quadruplets:

Again, odd oddd odd odd

6c4, again we have 15

6-lets

1 choice, 6c6

Thus 15+15+1 = 31

Not sure if correct, but I think it its.

I am really confused about this one, I thought the answer was 15 but that is wrong

Thats incorrect

thanks for the help!

deleted...

I need help with the subsets of S one

\(\angle APC = 115^\circ\\ \angle BPC = 65^\circ\\ \because CP = CB \\ \therefore \angle CBP = 65^\circ\\ \because AB = AC\\ \angle ACB = 65^\circ\\ \)

Then you consider △CPB to find angle PCB. The rest is trivial.

Even integers are multiples of 2, which means they are 2 times "something".

5 times 2 times "something" is 10 times "something". That means "5 times an even integer" is the multiple of 10.

The multiples of 10 (less than 500) are 10, 20, 30, 40, ..., 490.

Therefore there are 49 such integers.

Recall the definition of a^b.

\(a^b = \underbrace{a\times a \times a \times\cdots\times a}_{b\text{ times}}\)

That means 

\(10^2 = 10\times 10\\ 4^3 = 4\times 4 \times 4\)

The rest is simple.

Let a, b, c be the edges.

\(\begin{cases}ab = 3\\bc = 2\sqrt 3\\ca = \sqrt{15}\end{cases}\)

(1) * (3) / (2) : 

\(a^2 = \dfrac{3\sqrt{15}}{2\sqrt 3} = \dfrac{3\sqrt 5}2\\ a = \sqrt{\dfrac{3\sqrt 5}2}\)

Similarly, 

\(b = \sqrt{\dfrac6{5}\sqrt5}\) and \(c = \sqrt{2\sqrt 5}\)

Required ratio = b : c = \(\sqrt 3 : \sqrt 5\)

(y - 5)^2 = (x - 5)^2

|y - 5| = |x - 5|

y - 5 = x - 5 or y - 5 = 5 - x

y = x or y = 10 - x

The area of a regular hexagon A is related to its length L by 

\(A = \dfrac{3\sqrt 3}2 L^2\)

Consider the top white isosceles triangle.

The base is \(2L\sin 60^\circ = \sqrt 3 L\). This is also the length of the rectangle.

The width of the rectangle is \(L\), so the area of the rectangle is \(\sqrt 3 L^2 = \dfrac23 A\).

The area of rectangle is two thirds of the area of the hexagon, which is 60.

How to make a derivative function?
f (x) = 7 ^ 3-x / 2-8 / x;

Is this your function?

Это твоя функция?

\(f(x)=7^{\left(\frac{3-x}{2}\right)}-\frac{8}{x}\)

but... that is what the calculator says

I agree 10^500 is really large, ANDit's outside of the range of the calculator.

I think we only have 64 bits so minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807

yeah

10 with 500 zeros exceeds that

Maybe, who knows?

I think my TI non-graph calc. is only 16 or 32 bits.

Not really...

10^500 is constant

so it's not really infinity

K.

So I had an answer here and the second word of your answer or the the word after "give the answer a" is bad.

My answer just got flagged.

The equation implies that (a - 1) is a multiple of 13 and (b - 1) is a multiple of 11. 

The smallest possible a + b occurs when a - 1 = 13 and b - 1 = 11, which means min(a + b) = 25.

Let the capacity of the container = C

When 40% empty = 60% full

60%C - 40%C =20%C

20%C = 35 liters

Divide both sides by 20%

C =35 liters / 20%

C = 175 liters - capacity of the container.

1 is the answer

That answer is incorrect sorry...

Component form of a two-dimensional vector is (a, b), where a and b are real numbers.

First, we want to know what does (-2, 3) mean. It means the direction "two units to the left, and three units upwards".

The result of multiplying this vector by 6 means that going "two units to the left and three units upwards" 6 times.

In total, you would have gone 12 units to the left and 18 units upwards, which is (-12, 18).