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\(\frac{5(x+3)}{(x+3)(x-3)}=\frac{5}{x-3}\)

\(\frac{y-4}{4-y}=-1\)

\(\frac{5}{x-3}*-1=\frac{5}{3-x}\) which is answer choice \(\fbox a\)

With your problem, the factoring can result in more than one correct answer, but the process shown is good.

The "Newton-Raphson iteration method" has nothing to do with this problem.

Instead of trying to figure out the value of x, we can use clever squaring.

Square the first equation.

\((x+\frac{1}{x})^2= 3^2\)

\( x^2+1+1+\frac{1}{x^2}=9\)

\(x^2+\frac{1}{x^2}=7\)

Square this equation again.

\((x^2+\frac{1}{x^2})^2=7^2\)

\(x^4+1+1+\frac{1}{x^4}=49\)

\(x^4+\frac{1}{x^4}=47\)

a)  Since the deck contains 8 cards labeled "3" and 2 cards labeled "9",

     the total value of the cards is:  8 · 3 + 2 · 9  =  24 + 18  =  42.

     The expected value of one randomly drawn card is  42 / 10  =  4.2.

b)  An additional "9" is added to the deck: the total value is now:  8 · 3 + 3 · 9  =  24 + 27  =  51.

      The expected value is now  51 / 11  =  4.64    (approximately)

c)  Two additional "9"s are addeded to the deck.

      Are these two addition cards added immediately after step a or after step b?

      If they are added after step b, the totall value is now:   8 · 3 + 5 · 9  =  24 + 45  =  69.

      The expected value is now:  69 / 13  =  5.31

d)  This question is incomplete.

f(-2.2) = -2.2 - y = integer

We're trying to get rid of the fractional part 0.2. Since y > 0, y = 0.8

-2.2 + 0.8 = -1.4

First divide both sides by 2.

\(ny^2=n^2y-48\)

Then move all the variables to one side.

\(n^2y-ny^2=48\)

\(ny(n-y)=48\)

I factorized 48 and used trial and error to find

\(ny=12\)

\(n-y=4\)

Solve and find \(n=6, y=2\)

You have to use Newton-Raphson iteration method. You may have to look it up.
y =- 6 and n = - 4
y = 2 and n = - 4
y = - 6 and n = - 2
y = 4  and  n = - 2
y = 2  and  n = 6
y = 4  and  n = 6

3x-5=16

3x=21

x=7

Hint: if peter can peel two-thirds of his pail in half an hour,  it takes 45 minutes for him to peel a whole pail. The formula is \(\text {work load = time} \times \text{speed}\) (of course it's Pippin and Peter's speed combined). 

Your questions have already been answered in this thread:

I'm doing MBMT and I use web2.0 every so often, and have been for a couple years (check my profile.) This isn't allowed.

Your questions have already been answered in this thread:

or you could just look it up

Thanks!

The possible is the area of the triangle bounded by the x-axis, the y-axis, and the line y = -x + 6.

The endpoints of this triangle are (0,0), (6,0), and (0,6)  [Sorry; it isn't 81.]

The success is the area of the triangle bounded by the x-axis, the line y = -x + 6 and the line

y = -4x + 6.

The endpoints of this triangle are (1.5,0), (6,0) and (0,6).

Dividing the success by the possible will give you the probability.

Good thing you edited it. You can't post MBMT question bro

It's "hallo"

According to my science teacher and translator.

Ok I apologize for my error and for helping someone cheat

First off, the awnswer is NOT 31(I did it). And this person is a current participant in the MBMT Online Math Tournament. It is against the rules to use the internet to find solutions.

54-18 = 36.

36/2 = 18

Thus the larger number is 18+18 = 36.

If you don't understand anything feel free to ask.

Say that the distance of 1 side is 30 feet

So the first three, he spends 15 seconds, for the last, 6. so 21 seconds, for 120 feet.

21/120 = 7/40 as guest said.

Lets say there are q quarters.

There are 2q nickels, and q/2 dimes.

2q * 0.05 + (q/2)0.1 + 0.25q = 3.2

0.1q + 0.05q + 0.25q = 0.4q = 3.2

q = 3.2/0.4 = 32/4 = 8

8 quarters, 16 nickels, 4 dimes

8*0.25 = 2, 16*0.05 = 0.8, 4*0.1 = 0.4, correct!