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When lines are parallel their slope is the same. So we know the parallel line is y=-5x+b. We plug in the point(-4,-1) to find b.

y=-5x+b

-1=-5(-4)+b

-1=20+b

b=-21

So the equation is y=-5x-21.

Yes.

40% discount means that the discounted price is 60% of the original. After discount, the used book is $18, which is 60% of its original price, x. We form an equation:

18=60/100(x)

1800=60x

x=$ 30

y-4=2(x-6)

y-4=2x-12

y=2x-8

The slope of the line perpendicular must be -1/2. We then have y=-1/2x+b. We plug in the given point (-3,-5) to solve for b.

y=-1/2x+b

-5=-1/2(-3)+b

-5=3/2+b

b=-13/2

So the equation is y=-1/2x-13/2.

5x is 5x/(x/5) times as much as x/5.

5x/(x/5)

=5x*5/x

=25 times

Then x/5 is 1/25 as much as 5x.

1/25x100=4%

No, for example if you used a 25 and a 5 then no matter what you do it will only be a multile of five.  If you have any questions feel free to ask!

Your welcome!  Happy to help!

First lets pick out the data from the word problem,  There are 9 crayons and 3 children.  The problem wants us to figure out how many ways we can distrubute the crayons to the children.  Each crayon can go to 1 child and there are 9 crayons, so there are 9 x 3 = 27 possible ways to destrbute the crayons.  If this is confusing or you have any questions feel free to ask!

thank you tha makes sense now!!!!!!

Yep, I am

The tree is 6 feet tall and grows 15 feet so the first step would be to find out how much it grew.  Since 15-6=9 it grew 9 feet.  9 is 150% of 6 so the trees height increased by 150%.   If this is confusing or doesn't make sense feel free to ask a question!

                                     x² - 2x  =  0

Factor out the x-term:  x(x - 2)  =  0

Now, either                   x = 0          or          x - 2  =  0   --->   x  =  2

To win the tournament you will need to win two more games and not lose more than two games.

The various ways that you can win are:

WW             (½)(½)            =

WLW           (½)(½)(½)       =  

WLLW         (½)(½)(½)(½)  =

LWW           (½)(½)(½)       =

LWLW         (½)(½)(½)(½)  =

LLWW         (½)(½)(½)(½)  =

Calculate each of the above situations and add them together for your final answer.

me lol

I would suggest drawing this on a sheet of graph paper but make the distance from A to B to be 12, not 1.

This will make finding the points of reflection, and the distances, much easier.

However, the last step will be to divide the answer by 12.

Place A at the origin:  A = (0, 0)     B = (12, 0)     C = (12, 12)     D = (0, 12)

Also, since there will be many points of reflecttion, rename point X as point X₁.

Since X₁B = three-fourths of AB,  X₁ = (12, 9).

The point X₂ will be on side CD.  

The "angle going in" will equal the "angle coming out", so CX₂ / CX₁  =  AB / X₁B.

This makes  X₂ = (8, 12).

Point X₃ will be on side DA   --->   DX₃ / DX₂  =  CX₁ / CX₂   --->   X₃ = (0, 6).

Point X₄ will be on side AB   --->   X₄ = (8, 0).

Point X₅ will be on side BC   --->   X₅ = (12, 3).

Point X₆ will be point D   --->   X₆ = (0, 12).

Now, use the distance formula to find all the distances:

AX₁   =  sqrt( (12 - 0)² + (9 - 0)² )  =  15

X₁X₂  = sqrt( (8 - 12)² + (12 - 9)² )  =  5

X₂X₃  =  ...

X₃X₄  =  ...

X₄X₅  =  ...

X₅D   =  ...

Add these distances together and then divide by 12.

What's the first, does anyone know?

I think it is either 149 * \(\pi\) or 126 * \(\pi\).

The number in question is =142,857
142,857 x 2 =285,714
142,857 x 3 =428,571
142,857 x 4 =571,428
142,857 x 5 =714,285
142,857 x 6 =857,142

what sre you all doing in AOPS because I am doing prealgebra 2

Um I was here only a few months ago so I don't really know these people :(

Thanks anyways