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What do you not know?!?

That's correct! and nice explanation thanks :)

Soooo.. you need to find the point that is   3   / (3+1) = 3/4 of the way from a to b

x   from a to b  goes from 0 to -4     3/4 * -4 = -3     added to   0 =   -3

y   from a to b                    7 to 2 is -5     3/4 * -5 = -15/4    added to 7 is  13/4

85 - 7 candies taken by 1 child =78 candies left.

78 candies are distibuted among remaining 18 children

A + B =18

78 =3*A + 5*B, solve for A and B

A = 6 children who took 3 candies each.

B = 12 children who took 5 candies each.

Check:[6*3 + 5*12 + 1*7] =[18 + 60 + 7] = 85 candies.

2088
4 nCr 1 =3 - But leading zero does not count 0, 2, 8 =2 
4 nCr 2 = 7 - But leading zeros do not count 02, 08, 20, 28, 80, 82, 88 =5 
4 nCr 3 = 12 - But leading zeros do not count 028, 082, 088, 208, 280, 288, 802, 808, 820, 828, 880, 882 =9
Total = 2 + 5 + 9 = 16 possible numbers

Here is a hint:

Change z to a+bi. Since the magnitude is the square root of a^2+b^2, solve for that. 

To make myself more clear, let me show you how to do the left side, and then you can to the right side.

Once we have changed z to a+bi, we can subtract 3 from a. This will give us (a-3)+bi.

Now, squaring a and b, we get

a^2-6a+9+b^2 for the inside of the square root. Therefore, the left side is \(\sqrt {a^2-6a+9+b^2}\).

Now, try to do the right side, and solve the equation.

Here are some hints for each angle:

x: In a pentagon, the sum of the angles is 540 degrees. Since this is a regular pentagon, what can you do to get x? In other words, divide 540 by the amount of angles in the pentagon.

y: Since a regular pentagon has all equal sides, the triangle on the top is an isoceles triangle. Therefore, subtract x from 180 and have that equal to 2y. Then, solve for y.

z: Since the pentagon is rotatable, the bottom triangle is the same as the top. Once you have solved for y, subtract that from x, and you will have z. 

From the second equation   b = a+7    sub this into the third equation ...then solve for  'a'

   use this value of 'a'   in equation 2 or three to find  'b'   

      then use the values of 'a' and 'b'  in equation 1  to find 'c'

Hmm... To me, this looks like maybe homework? Instead of giving you the answer, here are some hints:

Add the last two equations together, what do you get?

I am lol...

Value of '?'? Do you mean c? If so, I can help, but in the future, please make sure there are no typos in your question, to make the answerer's life easier.

To begin, we first need to distribute 2(4+cy). This gives us 8+2cy. From here, we can subtract 8 from both sides and get 2cy=12y. Dividing both sides by y, we get 2c=12. Isolating the c, we get 6. Therefore, c is equal to 6.

ANYONE HERE??? ANYONE GONNA ANSWER ME???

(Sorry if i'm sounding rude but I need the answer in 5 min or less.

That isn't right... It is 4 possibiities for each ball so \(4^4=256\)

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Nice try! But that's incorrect

12 is wrong, too :(

Here is a VERY similar problem..... follow the same method to solve this system...

https://web2.0calc.com/questions/help-on-system#r1

I will assume you do not allow a leading zero

   this will be a 3 digit number to be less than 1000

     you have 3 choices for the first number  (since we cannot use zero)

        then you have 3 choices for the second number

          and finally 2 choices for the third number

              3 x 3 x 2 = 18 numbers BUT two of the choices are identical ('8' s)

                      so the options are divided by 2     18 / 2 = 9 numbers

Ok....incorrect...hmmmm

  no leading zero    so you have only two choices for the first digit   2  or  8

      then you have three choices for the next digit 

         and two for the last digit           12 numbers     (maybe?)   Just kinda guessing now.

The second equation defines 'y' ....sub this value of 'y' into the first equation....

    then you can solve for 'x'      With THIS value of 'x' , you can sub into either of the equations

      to compute 'y'.....    give it a try .....

We have to find the LCM of those numbers.

We can do these equations to find them out.

1=1*1

2=2*1

3=3*1

4=2^2

5=5*1

6=3*2

7=7*1

8=2^3

9=3^2

10=5*2

LCM=2^3 * 3^2 *5*7=2520.

Therefore smallest number which is divisible by 1,2,3,4,5,6,7,8,9 and 10 is 2520.

Yay!

The perimeter is AB + BC + AC.

BC  =  AK + KB  =  6 + 8  =  14

Since AK is an altitude, triangle(ABK) is a right triangle. 

Its bases are AK = 6 and KB = 8.

To find AB, use the Pythagoren Theorem:  AB²  =  AK² + KB²  =  6² + 8²

Complete this equation to find the value of AB.

Also, triangle(AKC) is a right triangle.

Its bases are KC = 6 and AK = 6.

To find AC:  AC²  =  KC² + AK²  =  6² + 6²

Complete this equation to find the value of AC.

Now, use:  AB + BC + AC to find the perimeter.

There are 7 + 4 + 9 = 20 balls altogether.

You can pick two balls of the same color if you:

1)  pick two red balls:  (7/20) x (6/19) = ........

2)  pick two yellow balls:  (4/20) x (3/19) = ......

or

3)  pick two green balls:  (9/20) x (8/19) = ........

You'll need to do the three individual calculations and add their answers together ...

we find that the slope is -1/3 and the y-intercept is (0,1) so the equation is y<=-1/3x+1

First, you substitute 1 in for x, and you will get \(3\cdot1^4-7\cdot1^3+2\cdot1^2-b+1=1\). 

Simplify.\(3-7+2-b+1=1\)

\(-1-b=1\)

\(b=-2\)