In triangle ABC, a, b, c are opposite angles A, B, C, respectively.
If c^2 = 2ab and a^2 + c^2 = 3b^2, then find angle A.
Let the triangle ABC be an isosceles triangle a = b = 2
c2 = 2ab
c2 = 8 c = sqrt(8)
a2 + c2 = 3b2
4 + 8 = 12
∠A = arccos[( c/2) / b] = 45º