I suppose 6?
1 x 2 x 3 = 6
2 x 3 x 4
3 x 4 x 5
4 5 6
I think the answer should be 6.
In every three consecutive integers, one of them must be a multiple of three. And there must be at least one multiple of two as well. So 3 x 2 = 6.
I hope this helped.
Thanks, all of you, it really helped.
And the answer is 16.
Isn't this forum for those who are over 16...?!?
Ratio 9 : S = S : T
Area = ( 9 / S )2 + 8 ( S / T )2
Area of a right triangle = 1/2 b h
you have 3 triangles of b,h 1) 3.5 x 9 2) 2 x 2 3) 2x5
and add a small square that is 2 x 2
3x^4+2x-1+h(x)=5x^2-6x-1 subtract 3x^4 + 2x -1 from both sides
h(x) = -3x^4 + 5x^2 - 8x
Let's take this term by term. We have 3x^4+2x-1 and 5x^2-6x-1. h(x) must have -3x^4 because all x^4 terms cancelled in the sum, 5x^2 because there was no x^2 term before so this must have been added, and -8x because 2x-8x=-6x.. So h(x) is -3x^4+5x^2-8x.
We can form an equation for the relationship between vegetable pizzas and pepperoni pizzas.
v=5p+3.
The total number of pizzas is v+p=51. Substitue 5p+3 for v and solve for p.
(5p+3)+p=51
6p+3=51
6p=48
p=8 pepperoni pizzas.
correction...
angle G = 0.785 rad
BI works out to 7 + 4*sqrt(2).
Each chord goes 2*75 = 150 degrees around the circle. It will then take 360/150*5 = 12 chords to go around the circle.
If (x,y) is the center of the circle and r is the radius, then
(x + 2)^2 + y^2 = r^2
(x - 2)^2 + y^2 = r^2
(x - 3)^2 + (y - 2)^2 = r^2
Subract equations:
8x + 2y - 9 = 0
x + 6y - 9 = 0
Solve: (x,y) = (18/23, 63/46)
angle A = 2.6179 rad
angle D = 1.5708 rad
angle G = 0.7569 rad
tan x = opposite / adjacent = 3/7
arctan(3/7) = x = ~~23o
No, you can't
4 L + 4 A = 10 is basically the same equation as
2 L + 2 A = 5 (just divided by 2)
Perimeter = 8 + 8 + w + w = 24
soooo w = 4
ratio w/l = 4/8 = 1/2
B = brandon distance
P = pat distance = 545 - B
B/100 + (545-B) / 90 = 5.75 solve for B = Brandon's distance ....then P = 545 - B
154º
48º
26º
106º
Slope , m = (y1-y2) / (x1-x2) = (10- -2) / ( 6-4) = 6
y = mx+b becomes y = 6x+b sub in oneof the points to calc 'b'
10 = 6(6) + b b = - 26
y = 6x-26
There wil be a 15 x^4 when the first terms are multiplied.....rules no choices out
there will be a -15 when the constants are multiplied so it is B or D
when the x tems are multiplied by the constants there will be a - 10x and a - 12x = - 22x so answer B
b+g =20 or b = 20-g
and g = 2/3b sub in the definition of b above
g = 2/3 (20-g)
g = 40/3 - 2/3 g
5/3 g = 40/3
5 g = 40
g = 8
The roots a and b are \(\frac{-5 \pm \sqrt{69}}{3} \)
so (a + 3)(b + 3) = \((-\frac{5 + \sqrt{69}}{3} + 3)(-\frac{5 - \sqrt{69}}{3} + 3) = \boxed{-21}\)
We want to find the expected vaue of j - i, where i and j are the positions of the jokers.
We can compute that
\(\sum (j - i) = \frac{n^3 - n}{3}\)
So the expected value is (n^3 - n)/3/C(n,2). For n = 54, this is 110/3.
The smallest n that works is 7.
