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I do not understand what a,b,c and d are.

Where is the picture?

Hello Guest!

\(sin (8°)=\frac{8}{\overline{UX}}\\ \overline{UX}= \frac{8}{sin(8°)}=\frac{8}{0.13917}=\color{blue}76.53 (C)\)

  !

FG = 10.5 units  

(I used a parallelogram called rectangle;  the ratio of width to length  is 4/5)

Using rise/run, it can be seen that the gradient of this line is 1/4.

The labelled y intercept is the value of b, thus 1

Therefore the equation of this line is equal to:

y=1/4x + 1

*Checked in online graphing tool*

How did you get 8/3 as the gradient here?

This is incorrect as the gradient is 1/4

e       and   r = 2e   and  j=1  <10

e + 2e + 1 <10

3e<9

e <3       soooo    r   <   6   

a ~ b/ c²  k    k is proprtionality constant    calculate k by subbing in the initial values

10 = 8/2^2   k

k =5

a = 5b/c²

a = 5(20)/5²  = .........

4^x = 27   log both sides

x log 4 = log27

x = log 27 / log4                          similarly  9^y = 16   yields    y = log 16 /log 9

xy becomes     (log 27 log16) / (log4 log9)   = 3

Two fair dice are tossed together once. Find the probability that the sum of the outcome is at least 10 

36 possible rolls.  6 of them total 10 or more.  So, the probability is 6/36 or 1/6    

1,1   1,2   1,3   1,4   1,5   1,6  

2,1   2,2   2,3   2,4   2,5   2,6  

3,1   3,2   3,3   3,4   3,5   3,6  

4,1   4,2   4,3   4,4   4,5   4,6  

5,1   5,2   5,3   5,4   5,5   5,6  

6,1   6,2   6,3   6,4   6,5   6,6 

_.

You can see straight off that x cannot be 0.

So

I would start by multiplying both sides by x^2

That will get rid of all the fractions and you will be left with just a quadratic to solve.

this is much the same as what guest has done.

This is not a hard one qwerty

first find angle ROP   

When subtended from the same arc, the angle at the centre is twice that at the circumference.

Then the distance is just a fraction of a circumference

From an online summation calculator:

n/2 ( 2a + (n-1)d)            n = 670    a = 1   d = 3

670/2 (2+ 669(3)) = 673015

Yah....that is why I was asking how kanisan got only '4'.....I wanted to see k's work so far....

   I got 4 and -2 also....  ~EP

I think that should be right since I remember doing it a while ago in one of my courses, and here, geno also got the same answer...

First, I solved for y,  \(y = \frac{kx - x}{3} = \frac{k - 1}{3} x.\) 
Substituting is next, \(3x + \frac{k - 1}{3} x = k \cdot \frac{k - 1}{3} x.\)
 

Solve, and get values of k are 4, -2. 

 :)

The slope appears to be 8/3, and the y-intercept appears to be 1. So the equation is y=8/3x+1.

that's not right, but thank you anyways!!!

How did you get '4'       Did you get another value for 'k' besides 4 ???   (Like when you factored a quadratic for k )     

a^3 + b^3 + c^3 = 22.

(x,y,z) = (4,-2*sqrt(3),-sqrt(2))

AB^2 = 2 + sqrt(3), AC^2 = 8, BC^2 = 8

thanks i appeciate it

Look under your first post.

Solve for x:
9 + 27/x + 8/x^2 = 0

Bring 9 + 27/x + 8/x^2 together using the common denominator x^2:

(9 x^2 + 27 x + 8)/x^2 = 0

Multiply both sides by x^2:
9 x^2 + 27 x + 8 = 0

The left hand side factors into a product with two terms:
(3 x + 1) (3 x + 8) = 0

Split into two equations:
3 x + 1 = 0 or 3 x + 8 = 0

Subtract 1 from both sides:
3 x = -1 or 3 x + 8 = 0

Divide both sides by 3:
x = -1/3 or 3 x + 8 = 0

Subtract 8 from both sides:
x = -1/3 or 3 x = -8

Divide both sides by 3:

 x = -1/3              or               x = -8/3