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Not 100% sure what "fixed costs" is, but im guessing thats how much money the company gets to use each day. This would mean that they have to pay 4.75 to make one hammer, so you would need 4.75x. Next, since they are given 400 to use, it would come up to C(x) = 4.75x + 400

From the equation y = -2/5(x) + 8, we can see that any perpendicular line will have 5/2(x) in it. Next, we try and get the line to go through the point (7,2). This means that when we plug in 7 as the x, we should be able to get 2 as the answer for the equation:

y = 5/2(x) +/- [ ... ]

2 = 5/2(7) +/- [ ... ]

2 = 35/2 +/- [ ... ]

-31/2

Now we add that to the equation:

y = 5/2(x) - 31/2

I don't understand the answer. Can you explain it?

thanks

942! = 2^935 * 3^467 * 5^233 * 7^155 * 11^92 * 13^77 * 17^58 * 19^51 * 23^41 * 29^33 * 31^30 * 37^25 * 41^22 * 43^21 * 47^20 * 53^17 * 59^15 * 61^15 * 67^14 * 71^13 * 73^12 * 79^11 * 83^11 * 89^10 * 97^9 * 101^9 * 103^9 * 107^8 * 109^8 * 113^8 * 127^7 * 131^7 * 137^6 * 139^6 * 149^6 * 151^6 * 157^6 * 163^5 * 167^5 * 173^5 * 179^5 * 181^5 * 191^4 * 193^4 * 197^4 * 199^4 * 211^4 * 223^4 * 227^4 * 229^4 * 233^4 * 239^3 * 241^3 * 251^3 * 257^3 * 263^3 * 269^3 * 271^3 * 277^3 * 281^3 * 283^3 * 293^3 * 307^3 * 311^3 * 313^3 * 317^2 * 331^2 * 337^2 * 347^2 * 349^2 * 353^2 * 359^2 * 367^2 * 373^2 * 379^2 * 383^2 * 389^2 * 397^2 * 401^2 * 409^2 * 419^2 * 421^2 * 431^2 * 433^2 * 439^2 * 443^2 * 449^2 * 457^2 * 461^2 * 463^2 * 467^2 * 479 * 487 * 491 * 499 * 503 * 509 * 521 * 523 * 541 * 547 * 557 * 563 * 569 * 571 * 577 * 587 * 593 * 599 * 601 * 607 * 613 * 617 * 619 * 631 * 641 * 643 * 647 * 653 * 659 * 661 * 673 * 677 * 683 * 691 * 701 * 709 * 719 * 727 * 733 * 739 * 743 * 751 * 757 * 761 * 769 * 773 * 787 * 797 * 809 * 811 * 821 * 823 * 827 * 829 * 839 * 853 * 857 * 859 * 863 * 877 * 881 * 883 * 887 * 907 * 911 * 919 * 929 * 937 * 941

The smallest n =233. Or 60^233.

Thanks

Look under your first post !.

a=1; b=1;d=a^2 * b^3; if(d==46656, goto4, goto5);printa, b; a++;if(a<250, goto2, 0);a=1;b++;if(b<250, goto2, discard=0; 

x              y

216         1
27          4
8            9
1            36

x=216 + 27 + 8 + 1 =252

Thanks!

Yes, Sir !.

1 Imperial gallon =4.54609 Liters

I km =0.62137 miles.

convert 5 Liters per 100 km to miles per Imperial gallons.

=56.5 miles per Imperial gallon.

so it 210

x=1;p=0; y=1;z=1;n=LCM(x,y,z);if(n==630 and GCD(x,y,z)==14, goto loop, goto next);loop:p=p+1;printp," =",x,y,z,"=", sum(x,y,z);next:x++;if(x<127, goto4,0);x=1;y++;if(y<127, goto4, 0);x=1;y=1;z++;if(z<127, goto4,0)

The smallest possible values of x = 14,  y = 70,  and  z =126

14 + 70 + 126 = 210

Thanks!

I think that incorrect

can you explain it?

The smallest possible vlaue of x + y + z is 144.

OMG SORRY! The question is: Can angle CAD=angle CBE? Explain.

The prime factorization of 942! starts 2^(927) * 3^(462) * 5^(231) * ...., so the largest n that works is 231.

(a,b) = (-3/2,1).

And... what's the question?¿?

-43 =F * R,   
3281 =F * R^4, solve for F, R

F = 43 (43/3281)^(1/3) - First Term 
R = -(3281/43)^(1/3) - Common Ratio.

Sum =(F * [(1 - R^N) / (1 - R)] =-3,644,446.06

LCM(3750, 5000) = 15,000 miles

 GCD(2015^3, 2018^3) = 1