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well p is obviously 36 so you get 146 = (4y+8)+(5y+3) so you get 9y+11, subtract 11 getting you 135=9y. Divide both sides by 9 and you get y is 15, plug it in so you get 78 degrees! Hope that helped :D

Solve this first-degree equation in one unknown, while writing all stages of the calculation

The equation : x-(1-x) √ 3=-5

Hello Guest!

$x-(1-x) \sqrt{ 3}=-5$       | multiply √3

$x-(\sqrt{3}-x\sqrt{3})=-5$   | (√3-x√3) multiply (-1)

$x-\sqrt{3}+x\sqrt{3}=-5$       | + √3

$x+x\sqrt{3}=-5+\sqrt{3}$       | x in front of the bracket

$x(1+\sqrt{3})=-5+\sqrt{3}$    | divide by the bracket

$x=\frac{-5+\sqrt{3}}{1+\sqrt{3}}\cdot\frac{1-\sqrt{3}}{1-\sqrt{3}}$            | multiply $\frac{1-\sqrt{3}}{1-\sqrt{3}}$

$x=\frac{-5+5 \sqrt{3}+\sqrt{3}-3}{1-3}$             | add

$x= \frac{-8+6\sqrt{3}}{-2}$                       | divide -2

$x=4-3\sqrt{3}$

  !

what is 9 3/8 x 2 2/3

Hello Guest!

Fraction x fraction = numerator x numerator and denominator x denominator.

$9\frac{3}{8}\cdot 2\frac{2}{3}=\frac{8\cdot 9+3}{8}\cdot \frac{3\cdot 2+2}{3}=\frac{75\cdot 8}{8\cdot 3}=\color{blue}25$

  !

= 9 9/24   + 2 16/24  = 11  25/24 = 12  1/24

1) shifted 3 to the RIGHT   to    4,-2

2) 2,-7       just reflect the given point across the axis of symmetry

arc sin ( cos5 - sin 75) = theta

= 1.735^o

No such triangle exists!!!  

YZ must be shorter than the sum of the lengths of XY and XZ!!!

A right-angled triangle has a perimeter of 1276 and the longest side of 533.  What is the length of the inradius?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Side:       c = 533

(743 - a)² + a² = 533²

a = 308

b = 743 - 308 = 435

Semiperimeter:     s = 1276 / 2 = 638

Triangle area:        A = 1/2(308 * 435) = 66990

Inradius:            r = A / s = 105

I went 7:30 - 3:30 when I was in 6th grade....30 min for lunch and a short recess in the AM and PM

Here’s GingerAle’s brilliant answer.

https://web2.0calc.com/questions/alrighty-my-first-one

quadrant  III

the imaginary  unit

quadrant II

Proof   (-8 -3i) *i^3  =  (-8 -3i) * -i  =  8i + 3i^2  =   -3  + 8i  (lies in Q2)

[PAB] = 1/2(2 * 6)            

[QAB] = 1/2(2 * 4.5)

[PAB] : [QAB] = 4 : 3

i had the same thing on my test lmao

k =  balls      n  = boxes

5 identical balls  into  3  distinguishable  boxes   (I'm assuming no restrictions.....a box may be  empty )

No.  of  ways =   C ( k + n - 1 ,  n -1)   =    C ( 5 + 3  -1  , 3 -1)  = C ( 7, 2)   =  21  ways

Mmmmm....I find   that   the hyperbola    x^2/4 +  y^2  =   1     tangent to  the ellipse    x^2 + 4y^2   = 4  at  (-2,0) and (2, 0)

See here   :    https://www.desmos.com/calculator/kiwougm8h6

Each point on the red graph is  twice as  high as that on the  blue graph....the transformation  is

y  =2f(x)

Find    'r' via pythag theorem

2^2 + (-2 sqrt3)^2 = r^2

r = 4             so answer A or B are possibles

   find angle   arctan (-2sqrt3 /2)  = -60 degrees   or  5pi/3           Do you see how to do it?

Here :   https://web2.0calc.com/questions/verify-the-identity-cosx-1-sinx-secx-tanx

Here :    https://web2.0calc.com/questions/in-the-diagram-arc-xy-is-and-arc-vw-is-find-arc-wy-in-degrees

Rectangular  coordinates =  ( r*cos ( theta) , r * sin  (theta))

a)   ( 4 cos 5pi/3, 4sin5pi/3)  =  ( 4cos300°, 4sin 300°) =  4 (1/2) , 4 (-sqrt (3)/2) )  = ( 2, - 2 sqrt (3) )

b)  (2, 11pi/6)  =  ( 2 cos 330 , 2 sin 330)  =  ( 2sqrt (3) /2  ,  2 (-1/2) ) =  (sqrt (3) ,- 1)

You should be able to  finish the last two.....let me  know if you get  stuck

I don't think you should have ten classes in 6th grade because the classes are not even a hour or maybe some of them are 1 hour long.Also, you still need lunch and you still have homework. Also, then you probably have study hall or something like that at some point and you should have at least 30 minutes or more for study hall if you are not doing a sport or something else for study hall. Each assignment for homework should take about 10 to 15 minutes each day.

thank you, later I found the the system of equations was

x+y=20

(y*90%)/(x+y)=72%

and I got x=4, y=16, just like you got, awesome soultion by you also.

https://web2.0calc.com/questions/drag-an-equation-variable-or-phrase-into-each-box

thank you so much 

Gatorade in ingrediants = gatorade in final product

x = amount of 90% mix

.9 x   = .72 (20)

x = 16 gallons     to make the final mixture volume 20 gallons, add 4 gallons of water.