All Answers

#1

+129840

+1

a) We have the tangent-secant theorem that says that

TU^2 = ST ( ST + RS) = ST (RT)

b)

TU^2 = 4 ( 16)

TU^2 = 64

TU = sqrt (64) = 8

CPhillFeb 9, 2021

#1

+373

+1

1. First cut must be at the 3-rd link. Then Samir has this 3-rd link cut as a single link; he has also the block of 2 links (the 1-st and the 2-nd links connected together); and then he has 3 links as the union ((1st + 2nd together) U 3rd).

2. Next cut must be at the 8-th link. Then, in addition to the set (A), Samir has - this 8-th link cut; - the block of 4 links (4th+5th+6th+7th all connected together), and then it is clear that combining this block of 4 links with what he just has in the set (A), he is able to have a) 4 links; b) 5=4+1 links; c) 6=4+2 links; d) 7=4+3 links; and e) 8=4+3+1(8th) links.

3. By continuing with this pattern, it is clear that (C) the next, third cut must be at the 8 + 8 + 1 = 17-th link.

4. The next (and the last), fourth cut must be at the 17 + 3 = 20-th link. Then it is OBVIOUS that having the sets (A), (B), (C) and additional 2 connected segments (18,19) and (21,22,23) and 1 cut link (20th) Samir will be able to present a) 18 = 17 +1; b) 19 = 17+2; c) 20 = 17+2+1; d) 21=17+3+1; e) 22=17+2+3; and, finally, all 23 links as well.

So, the problem is just solved and the ANSWER is: The cuts should be made at 3-rd; 8-th; 17-th; and 20-th links.

Hope this helped!

( ﾟдﾟ)つ Bye

TaliaArticulaFeb 9, 2021

#2

0

thanks

GuestFeb 9, 2021

#1

+22

+1

each season is 3 months long

Summer Fall Winter spring

+3 +3 +3 +3

It will be winter

NappeFeb 9, 2021

#2

+373

+1

Here, you can copy and paste this one if that's what you mean: ÷

Hope this helped!

( ﾟдﾟ)つ Bye

TaliaArticulaFeb 9, 2021

#2

+373

+2

Hey there, Guest!

You want to find the equation for a line that passes through the point (-3,9) and has a slope of 0.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 0. So you can right away fill in the equation for a line somewhat to read:

y=0x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-3,9). When x of the line is -3, y of the line must be 9.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-3,9).

So, why not plug in for x the number -3 and for y the number 9? This will allow us to solve for b for the particular line that passes through the point you gave!