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ty!!!!!!!!!!!!!!!!!!!!!!!!!!!

I remember  this  one from the  other  day.....it  just  wants  the area  between  sector BOA  and  triangle BOA

Area of sector  =  pi * 8^2 * (90/360)  =   16 pi

Area of triangle  BOA   = (1/2) (8)^2  =  32

Purple area =    16 pi -32  =   16  ( pi  - 2)

This is a mess, I'm adding onto this mess

https://web2.0calc.com/questions/help-me-out-plz

I've thought about it for like 3 seconds, and I don't think there is a solution.

If I solve any of the first variables, then substitude that result into the other equation, there's no solution.

Yeah uhh.

m=(7-3n)/4 

m=-(3n)/4+2 as well

Yay!

_{\([asy] size(4cm); pair o=(0,0); pair a=(-sqrt(2)/2,-sqrt(2)/2); pair b=(sqrt(2)/2,-sqrt(2)/2); path p=Arc(o,1,225,315)--b--a--cycle; fill(p,purple); dot(o); dot(a); dot(b); draw(o--b--a--o); draw(a/8--(a+b)/8--b/8); draw(Circle(o,1)); label("$O$",o,N); label("$A$",a,SW); label("$B$",b,SE); [/asy]\)}

Need to see the PURPLE area ...is it in the 90 degree area ...or the 270 degree area ...or other?

thanks for the help 

1/( 1+2+3) =   1/6 of 180 = angle 1  = 30 degrees

2/6 =  1/3  of 180 = angle 2  = 60 degrees

3/6 = 1/2 of 180 = angle 3  =  90  degrees

f(x)+2=ax^+bx^4+cx^3+2=(x^3+3x^2+3x+1)(dx^2+ex+f) (my head hurts)

If you multiply it out, you get these "variables"

a=d, b=e+3d, c=f+3e+3d, d+3e+3f=0, e+3f=0, f=2

Solve for abcdef

f(x)=ax^5+bx^4+cx^3

Yay!

You have to have a Desmos account (free)   ....then you can 'Save' it and the link is there.....

l * w = 315         l = 315/w

(l+2)(w-2) = 315 -21 = 294       sub red into this

(315/w + 2) (w-2) = 294

    315 - 630/w   + 2w  -4   - 294 = 0

       2w^2 + 17 w - 630 = 0              Quadratic Formula shows   w = 14  cm        then l = 315/14 = 22.5   cm   (originally)

angle a is 360-110-73-90 which is 87

angle b is 360- 57-61-128 which is 114

angle c is 360-127-103-87 which is 43

desmos is a life saver, but I don't know how CPhill can make it bend to his will, how does he make it into a link?

x - 2y  + 4    = 0           rearrange  as

x =  2y  - 4                    sub this into the second  equation  for  x

5 ( 2y  -4)  + 5y    +  18  =  0      simplify

10y  - 20  +  5y +  18   =  0

15y  - 2  =   0

15y =   2

y =  2 /15

So

x  = 2(2/15)  - 4    =   4/15   - 4    =    4/15  - 60/15  =    -56 / 15 

no that one is -1 but this one +2 very similar 

I believe this question is one heureka already solved, the link is

https://web2.0calc.com/questions/find-a-polynomial-f-x-of-degree-5-such-that-both

Yay!

1/3 =   10 / 30         3/5 = 18/30

so you are looking at  M   between   10   and   18    ( non-inclusive)        11 12 13  14  15  16  17     <======== how many is that?

x=−56/15,y=2/15 solve by subsitution 

DItto on WolframAlpha    and a thumbs up to Desmos Graphing Calculator

   other various calculators  :    summation calculator      Quadratic Formula Calculator     etc

P is in an isoc triangle ...so two angles are equal    and   all three sum to 180

  from the diagram there are two angles = 62

      180 - 62 - 62 = p

The quadrilateral    has 4 angles which sum to 360

      the angle at E = 180 - 62    ( because they form a straight line)

                   (180 - 62)        + 90    +   132       +   q   = 360                          You should be able to finish from here !

Depends....I use  the calc  for some things.....I rely on WolframAlpha  more often

It's great for  checking equations, etc.

Volume of a cone    1/3 pi r^2 h   = 1/3 pi 4^2 * 12    in³

Volume of cylinder = pi r^2 h       = pi 3^2 * 8     in³                     I'll let you finish   

I sometimes use the calculator when I am on the Forum.....but most of the time I use a handheld ...or my phone calc (at night....my handheld is Solar)...

Varxaax says it all !