Hi Maths solver,
I have played with it but I have no idea.
Is the worked answer given?
Find the coefficient of y^4 in the expansion of (2y-7)^5.
Hello Guest!
\((2y-7)^5=32y^5\ {\color{blue}-560}\ y^4+3920y^3-13720y^2+24010y-16807\)
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It's too long to post so here's the second part:
1
Sorry! I will proofread next time.
A mathematician works for thours per day and solves p problems per hour, where t and p are positive integers and 1
3/4 of the cars are black.
1/4 of the cars are not black.
1/4 * 4/7 = 1/7 of the cars are blue
3/28 of the cars are silver.
3/28x = 9
Solve x.
=^._.^=
f(i) = 2i (since i is not real)
f(1) = 1i (since 1 is real)
Solve the other 2 values and add them up.
*You could also solve this problem by noticing that for every f(x) term, there's also a f(-x).
number of 20c coins = x
number of 50c coins = 80-x
1/2(x) + 1/2(80-x) = 80 - 46
Solve for x :))
The problem isn't complete.
(2^2) = 4
(2^3) = 8
(2^4) = 16
(2^2)^10 * (2^3)^20 * (2^4)^30
Can you take it from here?
CPhill, HELP!!!!
How many revolutions would a horse 18 feet from the center have to make?
\(way=\\ 2\pi r_1\cdot n=2\pi r_2\cdot x\ |\ :2\pi\\ 24ft\cdot 32=18ft\cdot x\ |\ :18ft\\ \dfrac{24ft\cdot 32}{18ft}=x\)
\(x=42,\overline 6\)
The horse would have to do 42 2/3 revolutions.
Find all complex numbers z such that z^4=-4
\(z\in \{-1-i,-1+i,1-i,1+i\}\)
In 3 days each grdener will put in 18 hours
2 gardeners will work 36 hours
3 gardeners will manage 54 hours...... so I suggest 3 gardeners to make the 3 day deadline
you got it wrong the second part should have been -3/2 instead of -2/3 the answer is -8/3
For the 'x' portion -6x(10) + 7t x = - 39 x
-60 x + 7tx = - 39x
7tx = 21x
t = 3
a = K * b/c solve for the proportionality constant 'K' with the first numbers given
3 = K * 5/9
K = 27/5
a = 27/5 b/c now sub in the second a and b
4 = 27/5 3/c
c = 27/5 * 3/4 = 4.05
3 - 4 -5 is a right triangle area = 1/2 L1 * L2 = 1/2 * 3 * 4 = 6 units2
John: 48 ÷ (1 - 3/5)
= 48*5/2
= 120 points
Peter: x - 1/3x = (120 - 48) + 18
2/3x = 90
x = 135 points
John: 120 points
Peter: 135 points
Angle BYX = 1/2(180 - 80) = 50º
Angle AYX = 180 - 50 = 130º
white : x
blue : y
\( {24 - x \over 28 - x + 40 - y}{}{} = \)\({3\over 4}\) \( {28 - x \over 68-x-y}\)\( = {3 \over 4}\) { { { \( {35 + y \over 10 + x 35 + y} = \) \( {4 \over 5}\) { \({35 + y\over 45 + x + y}\)\( = {4 \over 5}\)
{ 3 * 18 - 3x - 3y = 4 * 28 - 4x
{ 4 * 45 + 4x + 4y = 34 * 5 + 5y
{ x = 7
{ y = 33
So white : 7 blue : 33
20 full circles
The expected value is 9/32.
Sum of ingredients = sum in final solution
x = amount of 25 % acid content: .25x
10 = amount of 12% .12(10)
fianl product = .20 (10+x)
.25x + .12(10) = .20 (10+ x) solve for 'x' = the amount of 25% to be used in gallons
Expected value is computed by multiplying all of the possible outcomes by their probabilities, and then summing. $8/10$ of the time we draw a 3 and $2/10$ of the time we draw a 9. Therefore the expected value is \[3\cdot\frac{8}{10} + 9\cdot\frac{2}{10} = \boxed{\frac{21}{5}}.\]
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