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2x - 5 <= -x + 12    add x to both sides of the equation

3x -5 <= 12           add 5 to both sides

3x <= 17              divide both sides by 3

x <= 17/3                 

                (-inf, 17/3]

6 out of every 15 have been in an accident

how many 15's are there in 120?       Eight

     8 x  6 = 48  of 120   might have been in anaccident

h = 13 meters

13 = -5t^2 + 20t + 3

-5t^2 + 20t -10 = 0           we can simplify this a bit by dividing through by -5

t^2 -4t +2 = 0         Now use the quadratic formula to find the t values (two of them) ...one will be for the ball on the way UP

                                       the larger one will be for whe the ball is coming DOWN .

a = 1    b= -4    c = 2

\(t = {-(-4) \pm \sqrt{(-4)^2-4(1)(2)} \over 2(1)}\)     I will let you finish.....

Look at the graph and find the point where it is equal to -1    then scan vertically to the x-axis value which will be the value of 'c'

The point    (3, 7 ) should be on the graph    because    (9,7) is  (3^2 , 7)

         sum = 10

How much red is in the original 20 quarts ?      .25 (20) = 5 quarts

    now add 4 more quarts for a total of 9 quarts in a total of   24 quarts       9/24 * 100% = 37.5 % red

Please Help me Soon

x + y = 25 

and 

x - y = 18

Use elimination 

2y = 7

y = 3.5

x = 21.5

xy = 21.5*3.5 = 75.25 or as a mixed number, 75 and 1/4.

I suppose you are learning interpolation .... a type of extimation that assumes the graph is linear between two points (2.98 and 3.01 in this case)

from (f(2.98) to f (3.01) is     1.96 - 2.08 =  - .12   

   (3.01 - 2.98)  is .03

-.12/.03 = -4      the graph changes   -4    per   1 change in f(x)

for   .01   change (from   2.98 to 2.99)

       it will be   2.08  - 4(.01) = 2.04  

As follows:

A fox, a coyote, and a wolf weigh a total of 120 pounds. The ratio of the weight of the fox to the weight of the coyote is 3:8. The weight of the coyote is 32 pounds. What is the weight of the wolf?

f + c + w = 120

f/c = 3/8

c = 32

f/32 = 3/8

f = 12

w = 70

The manual solution of Q is given above. However, if you want to get an online solution then there are many online calculators that provide multiple online calculators to use. A few of the very useful and important which I've found are mentioned below :

As follows:

Typo:

\(\begin{array}{|rcll|} \hline ABCD &=& A^2B^2 \\ ABCD &=& 7^211^2 \\ \mathbf{ABCD} &=& \mathbf{5929} \\ \hline \end{array}\)

Find the value of t such that (5x^2 - 6x + 7)(4x^2 +tx + 10) = 20x^4 -9x^3+ 60x^2 - 39x + 70.

Hello Guest!

\( (5x^2 - 6x + 7)(4x^2 +{\color{blue}tx} + 10) =20x^4 -9x^3+ 60x^2 - 39x + 70\)

\((20x^4 -9x^3+ 60x^2 - 39x + 70): (5x^2 - 6x + 7)\\ =4x^2 +{\color{blue}3x} + 10\)

\(t=3\)

  !

Solve the inequality k^2 - 7k + 12.25 > 0.

Hello Guest!

\(k^2-7k+12.25>0\\ k=3.5\pm \sqrt{12.25-(<12.25)}\\ \color{blue}k\neq3.5\)

\(k\in \mathbb R\ |k\neq 3.5\)

  !

Four positive integers \(A\), \(B\), \(C\) and \(D\) have a sum of \(36\).
If \(A+2 = B-2 = C+2 = D-2\),
what is the value of the product \(ABCD\)?

\(\begin{array}{|rcll|} \hline A+2 &=& C+2 \\ \mathbf{A} &=& \mathbf{C} \\ \hline \end{array} \begin{array}{|rcll|} \hline B-2 &=& D-2 \\ \mathbf{B} &=& \mathbf{D} \\ \hline \end{array}\)

\(\begin{array}{|rcll|} \hline A+B+C+D &=& 36 \\ A+B+A+B &=& 36 \\ 2A+2B &=& 36 \quad | \quad : 2 \\ A+B &=& 18 \qquad (1) \\ \hline \end{array} \begin{array}{|rcll|} \hline A+2 &=&B-2 \\ A-B &=&-4 \qquad (2) \\ \hline \end{array}\)

\(\begin{array}{|lrcll|} \hline (1)+(2): & 2A &=& 18-4 \\ & 2A &=& 14 \quad | \quad : 2 \\ &\mathbf{A} &=& \mathbf{7} \\ \hline \end{array} \begin{array}{|lrcll|} \hline (1)-(2): & 2B &=& 18+4 \\ & 2B &=& 22 \quad | \quad : 2 \\ &\mathbf{B} &=& \mathbf{11} \\ \hline \end{array}\)

\(\begin{array}{|rcll|} \hline ABCD &=& A^2B^2 \\ ABCD &=& 7^21^2 \\ \mathbf{ABCD} &=& \mathbf{5929} \\ \hline \end{array}\)

120 + 720 + 5040 + 40320 + 362880 + 3628800......

which is 20 + 20 + 40 + 20 + 80 + 00 +00 +00.......,

which means last two digit is: 80

The product of my numbers is 8*4 = 32.

Find the number in the form x3579x that is divisible by 42.

335790 / 42 = 7995

Answer: 8

Solution:

Combining denominators on left, and then removing it from both sides gives

A(x+1) + B(x-1) = x + 8

Two equations can be found from this:

A + B = 1

A - B = 8

Similar question

https://web2.0calc.com/questions/please-explain-this-inscribed-angle-quesition

100% - 12% = 88%

15% of 88% = 13.2%

Total discount = 25.2%

wrong it was 6

What is the coefficient of x^2 when -5x^3 - 5x^2 - 7x + 1 is multiplied by x^2 + 6x + 1 and the like terms are combined?

Hello Guest!

\((-5x^3 - 5x^2 - 7x + 1) ( x^2 + 6x + 1 )=\color{blue}-5x^5-35x^4-42x^3-46x+1\)

\(The\ coefficient\ of\ x^2\ is\ 0.\)

  !

Simplify the following:
(2y-1)(4y^{10}+2y^9+3y^8+5y^7).
Express your answer as a polynomial with the degrees of the terms in decreasing order.

Hello Guest!

\((2y-1)(4y^{10}+2y^9+3y^8+5y^7)=\color{blue}8y^{11}+4y^9+7y^8-5y^7\)

  !