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$(x\color{red}^1\color{black} -1 ) f(x) = 3x\color{red}^8\color{black} + x^3 - 25x^2 + 38x - 17$

8-1=7

$(-6)^3*=-6*-6*-6=?\\ (-6)^2=-6*-6=?$

You can finish it.

The sum of three different numbers is 67. The two larger numbers differ by 7 and the two smaller numbers differ by 8. What is the value of the largest number?     

Call the three numbers A, B, and C in the order from smallest to largest 

A                             B                               C  

|<------------ 8 ------------>|<------------ 7 ------------>|   

|<--------------------------- 67 ---------------------------->|                                                                  |  

A + (A + 8) + (A + 8 + 7)  =  67  

3A + 23                          =  67  

3A                                 =  67 – 23  

3A                                 =  44  

  A                                 =  44/3  =  14-2/3

A  =  14-2/3  

B  =  22-2/3  

C  =  29-2/3  

_.

The sum of all the solutions is 360 degrees.

The maximum possible value of N is 111.

$c_1 + c_2 + c_3 = 2$.

My name is Allygator0777 

See https://web2.0calc.com/questions/arithmetic-sequence_29

See https://web2.0calc.com/questions/average_9

See https://web2.0calc.com/questions/stuck-on-counting-question

At my office, 16 people own cats, 11 people own dogs, and 7 people own both cats and dogs. How many people own a cat or a dog?

(Remember that in mathematics, the word "or" is used in the inclusive sense. So if you own both a cat and a dog, then you are included in the category of people "who own a cat or a dog".)

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There are 20 people who own cats and dogs. 

(16 - 7) + (11 - 7) = 13

Soo, only 13 people own a cat or a dog. 

7 people own both cats and dogs.

The equipment will equal 247 dollars in base ten and the money per hour will be 72. So the answer is 3.5*72+247=499.

On Monday Farhan sold 150 buns. On Tuesday he sold 1/4 of the remainder. Then he had 1/3 of the buns left. How many buns did he have at first?

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Total buns => x

This question is similar to this::::: https://web2.0calc.com/questions/fractions_97630

In the primary school library, there were 221 more fiction books than non-fiction books. If 3/5
of the non-fiction books and 4/7 of the fiction books were borrowed, the remaining fiction
books will be twice as much as the non-fiction books. Find the number of non-fiction books in the library at first.

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Fiction books => 221+x               Non-fiction books => x

There are 255 non-fiction books.

corrections:

(50 + x - 1/3(50 + x)) / (x - 3/5x) = 2   

The number of terms is 55.

The third root is 3/2.

5m-3 > 8m+21 + 7m+3

5m-3 > 15m + 24

5m > 15m +27

-10m > 27

10m < -27

m < $-\frac{27}{10}$

m < $-2\frac{7}{10}$

The greatest integer value for m would be -3.

There are 18 people who own a cat or a dog.

There are 10 ways to pick a project manager

$\binom{9}{2} = \frac{9 \times 8}{2 \times 1} = 36$ ways to pick two deputy project managers

$\binom{7}{5} = \binom{7}{2} = \frac{7 \times 6}{2 \times 1} = 21$ways to pick five engineers

$10 \times 36 \times 21 = \boxed{7560}$

The minimum value is 9/25.

By Cauchy-Schwarz, the minimum value is 1/n.

Its okie, thank you so much! c: