$$\frac{1}{4} \times \frac{3}{2} \times \frac{8}{9}$$
Start by "simplifying" if you can like so:
$$\frac{1}{{\not}4\;1} \times \frac{3}{2} \times \frac{{\not}8\;2}{9}$$
$$\frac{1}{1} \times \frac{3}{2} \times \frac{2}{9}$$
We can do this again with the 3 and 9 like so:
$$\frac{1}{1} \times \frac{{\not}3\;1}{2} \times \frac{2}{{\not}9\;3}$$
$$\frac{1}{1} \times \frac{1}{2} \times \frac{2}{3}$$
Multiply the tops together. Then multiply the bottoms together:
$$\frac{1\times1\times2}{1\times2\times3}$$
$$\frac{2}{6}$$
Now reduce the fraction by dividing the top and bottom by 2:
$$\frac{2\div2}{6\div2}$$
$$\frac{1}{3}$$
And that's that!
