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Yes good it is definitely one of the top ones.

The right side is the same for both so you only need to consider the left side.

g(x)=x

that is like  y=x

So you can look at any points.

If x is 0 then y would have to be 0  So (0,0) would have to be on the graph.

So which is the correct graph?

Let me write it again

Find the unique four-digit integer  with these properties:

 The last digit (the units digit) of this four digit number is 9 .

 The digits of  the this four digit number add up to 27.

 Two digits of this four digit number are the same.

  is a perfect square.

The quarter is for giants, not us. 

Your question isn't fully complete. 

The 4th clue alone narrows down the number to 68 possibilities, but we can not go any farther, because the question is incomplete.

I think its either the first left one or the first right one because of the closed circle on -3, but I'm not sure about the other line 

Please present some of your own input.  

example:

Which ones can you rule out.

Do you think you know the answer etc

Other answerers:

Please allow loona to interact with me.  Please do not answer over me.

Oh thank you so much CPhill!!! 

5 hr 20 min  = 5 + 1/3 hr  = 16/3  hr

6 hr  40  min =   6 + 2/3 hr  =  20/3 hr

Avg rate =   

Total distance /  Total Time  =

[ 300 + 360 ]   /   [ 16/3 + 20/3 ]  =

660   / [ 36/3 ]  =

660  / 12  =

55  mph

Huh, you talking about the first one or the second one ?

Ill walk you through the first one

Sorry about the unblock sign I took a picture.

The x values are getting begger by 1

The y values are getting bigger by 2

So there will be 2x as a part of the answer.

I'll added another row inbetween to show you what I have so far

No to get from the 2x row to the y row I will have to subtract 1

y = 2x-1

Note

If you graph it, it will a line with gradient of 2 and y intercept of -1 .  

Every point on that line will make this equation true.   

I remember how much problems this initially gave me but once you get the hang of them they are not that hard.  :)

Now you try the second one.  And we should do a whole heap more after that.

Triangle XYZ  is isosceles   (XZ = YZ)  with a base of 25   and a height of 20

[XYZ]  = (1/2) ( 25 ) ( 20)  =  250

Note  that in triangle   XYM, GY and  HM are medians

And triangle  HYM   is similar to triangle XYZ  because HY  = XY/2  and MY = ZX / 2  = ZY/2

And the scale factor of  triangle HYM  to triangle XYZ =  (1/2)

So  the area of triangle  HYM =  (scale factor )^2  * ( area of XYZ)  =  (1/4)(250) =  125/2

And the areas of triangles  HYM , XHM and XYG are the same

So T is  the intersection of  medians GY and HM in triangle XM

And by the property of intersecting medians,   HT =  1/3 of HM

So, since they are on the  same base, triangle HYT = (1/3)area of triangle HYM =  (125/2) /3 =  125/6

Since [ XYG ] =  125/2

Then  [XGTH]  has an area of  (2/3) (125/2)   = 125 / 3

But since triangles XHM and XYG have the same areas and XGTH is common to each, then the area of triangle MTG =  [ XHM ]  - [ XGTH]  =   125/2  - 125/3 =   125 / 6

You are refering to this question?

D is correct

helppp

Avg  =   (120 + 144 + 143 + 111  +  167 ) /  5 =    ????

There is an easier way to do this but I've forgotten the method.....here's a clumsier way  !!!!

Square  both sides

79 + 24sqrt (7) =   a^2  + 2absqrt (7)  + b^2 * c

This implies  that

c = 7  

 24 = 2ab

12  = ab

  Testing some values

       a           b                         a^2        b^2 * c              a^2 + b^2 * c =  79   ???

       1           12                        1           144 * 7                      No

       2            6                         4            36 * 7                       No

       3            4                         9            16 * 7                       No

       4            3                       16             9 * 7                       Yes

So     sqrt  [ 79 + 24sqrt 7 ]  =      sqrt  [ ( 4 + 3sqrt 7)^2 ]     =      4 + 3sqrt 7

So    a =  4   b = 3   and c = 7   

abc  =   4 * 3 * 7   =    84 

It is supposed to be called Firdaus

Thank you!!!

Convert from atoms to grams:
2.3×10^24 atoms silver (Ag)

Determine the number of atoms, N_atoms:
N_atoms = 2.3×10^24 atoms

Look up Avogadro's constant, N_A, to find the number of atoms in a mole:
N_A = 6.022×10^23 atoms/mol

Divide N_atoms by N_A to convert to the amount of substance, n:
n = N_atoms/N_A = N_atoms/1×1/N_A = (2.3×10^24 atoms)/1×(1 mol)/(6.022×10^23 atoms) = 3.819 mol

Determine the molar mass, M, of Ag:
M = 107.8682 g/mol

Multiply n by M to convert to the mass, m:

m = n×M = (3.819 mol)/1×(107.8682 g)/(1 mol) = 411.9745 g

We can model this with the sine function

We have this form

y  =  Asin (Bx)

y = the displacement   at any time, x

A = the amplitude =  7 in

x= time in sec

The period =  8s

B =   2pi / 8  =  pi/4

The function  is     y =  7sin [ (pi / 4)  x ] 

Here's a graph  :   https://www.desmos.com/calculator/urhpnycwzv

THAT is a really BIG quarter !     2.4 inches in diameter....

I barely remember this but I'll take my best shot

Note  that    as  x approaches  6, the  function   12x - 36   =  12 (6) - 36  =   72  -36  =    approaches 36

And as x approaches 6, the function x^2  =  6^2 =  approaches  36

So.....by the Squeeze Theorem......f(x)  also approaches 36  as x approaches 6  [ i.e., the limit  =36 ] 

(x^2 - 4x + 2) + (x^2 - 5x + 2) = 1  simplify as

2x^2 - 9x + 3  =   0

This will  have two real roots

In the form    ax^2  + bx + c ,  the sum of these =    -b / a    =     9 /  2

Here's a similar problem  :

https://web2.0calc.com/questions/pls-help_10037

Since we know that f(4) = 1, we can plug that information into the second equation and get:

f(2*4) = 3f(4)

f(8) = 3*1

f(8) = 3

f(2*8) = 3f(8)

f(16) = 3*3

f(16) = 9

f(2*16) = 3f(16)

f(32) = 3*9

f(32) = 27

f(2*32) = 3f(32)

f(64) = 3*27

f(64) = 81

Hope this helped. Let me know if I did anything wrong!

Call the amount that Adam had originally  =  A

Call the amount that Friday  had originaly = F

We  have these two  equations

(A - 9) / F  =   2/7

A / ( F - 9)  =  7/11

Cross-multiply in each case

7 (A - 9)  = 2F

11A  = 7 (F - 9)                 simplify  both

7A  - 63   = 2F                      (1)

11A =  7F - 63                  rearrange  both as

7A - 2F  =  63

11A - 7F  = - 63            multiply  the first equation by -7   and the second by 2

-49A  + 14F  = -441

22A  -   14F  =  -126           add these

-27A  = -567

A = -567 / -27   =   21     ( Adam originally had $21  )

And using (1)  to find F

7(21)  - 63  =  2F

147 - 63  =  2F

84  = 2F

84/2   = F =   42    (   Friday originally had $42 )  

They originally had  $63  dollars combined