Send a polite private message to a moderator asking for it to be unlocked.
Make sure you include the address in a link.
You are a member so you can do this..
If you were a guest you could do the same thing but it would have to be in a public post. (which is less likely to be seen)
20130118 =
12^2=144= 0 mod 8
therefore 12 ^ anynumber greater than 2 is also 0 mod 8
so
\(20130118_{12}\;\mod8 \\ = 18_{12}\mod8\\ =20_{10}\mod10 \\ =4\)
Let the number of hours flying downwind==H
18H ==Distance travelled downwind.
[18H - 5] / 15 ==18H/18
H == 5/3 - hours spent flying downwind
[18*5/3 - 5] / 15 + 5/15==2 - hours spent flying back to its nest.
Total distance==[5/3 * 18] * 2 ==60 miles.
5/3 + 2 == 11 / 3 ==3 hours + 40 minutes - total time spent flying back and forth.
Oh okay, thanks!
So would the answers be 3, -2,2-sqrt5 and 2+sqrt5..?
30,60,90,120,150,180,210,240,270,300,330,360,390,420,450,480,510,540,570,600\(\cdots\)
30x=y, ve a desmos.com y busca y para obtener divisores de 30
Is there a typo ?
What happened to the -1/9 ?
Where did the 1/8 come from ?
f(t) = (t - 3)(t+2)(t^2 -4t +7)
The area is the interior of the circle centre the origin and radius 5.
It does not include the circle itself.
Im not sure what that is, but this is school homework I got. So help would be appreciated
Hi Guest!
\(x+y=15 \hspace{2cm} (1) \\ x-y=3 \hspace{2.215cm} (2) \\ \)
Now, let us add equations (1) and (2):
\((x+y)+(x-y)=15+3 \\ \iff 2x=18 \\ x=\dfrac{18}{2}=9\)
Substitute in (1):
\(9+y=15 \implies y=6\)
Therefore, \((x,y)=(9,6)\) is the solution to this system of two equations.
I hope this helps!
divide both the numerator and denominator by 2:
\(\text{To get: }\dfrac{3}{4}\)
ok thanks
One has three letters, two has three letters, three has five letters, etc..
I give up :)
The ratio of percussionists to marching instruments is 2:13
Thus 15x = 150, where x is one unit.
x = 10 so there are 20 percussionists and 130 marching instruments
This website gives a good description on how to improve grades in calculus:
https://tutorbin.com/blog/how-to-improve-grades-in-calculus
The minus sign takes priority over the positive sign (positive x negative = negative). So open up the parenthesis: *use parity*
5 - 3 + 2 - 30
-26
z^4 = (z^2)^2
z^2 = pm sqrt(-4)
z^2 = +- 2i
z = sqrt(2i) or sqrt(-2i) or -sqrt(2i) or -sqrt(-2i)
I trust you can express it in a + bi. gl
Hint: does something with the english alphabet.
You don't need to, as long as you have it graphed, you can tell at which point the line and the exponential function intersect (if intersected at 2 points pick the one in which the functions are pointing or travelling at), and then determine which function is going to that point faster.
An exponential function is basically a log function, so technically yes. (Graph w/ a logarithmic function).
f(x) = x^2 + 6x + 7
f(x) > 2
x^2 + 6x + 7 > 2
x^2 + 6x + 5 > 0
(x + 5)(x + 1) > 0
Either both positive or both negative.
x > -1
x < -5
