The vertical asymptote of f(x) is x = 2/2 = 1. The vertical asymptote of g(x) is x = d. Since the graphs of f(x) and g(x) have the same vertical asymptote, then d = 1.
The oblique asymptotes of f(x) and g(x) are perpendicular, and they intersect on the y-axis. This means that the slopes of the oblique asymptotes are negative reciprocals of each other. The slope of the oblique asymptote of f(x) is -1/2. The slope of the oblique asymptote of g(x) is 2a. Since the slopes are negative reciprocals of each other, then 2a = -1/2. This gives us a = -1/4.
The point of intersection of the graphs of f(x) and g(x) that does not lie on the line x = -2 is the point where the oblique asymptotes intersect. This is the point where x = 1.
Plugging x = 1 into f(x) and g(x), we get:
f(1) = (1^2 - 6(1) + 6)/(2(1) - 4) = -1/2 g(1) = (a(1)^2 + b(1) + c)/(1 - d) = (-1/4(1) + b + c)/(1 - 1) = b + c
Since the oblique asymptotes of f(x) and g(x) intersect at y = -1/2, then b + c = -1/2.
We are given that the graphs of f(x) and g(x) have two intersection points, one of which is on the line x = -2. The point of intersection of the graphs of f(x) and g(x) on the line x = -2 is (-2, 3).
Plugging x = -2 into f(x) and g(x), we get:
f(-2) = (-2)^2 - 6(-2) + 6)/(2(-2) - 4) = 12/-4 = -3 g(-2) = (a(-2)^2 + b(-2) + c)/(-2 - 1) = (4a - 2b + c)/-3
Since the graphs of f(x) and g(x) have two intersection points, then the equations f(-2) = -3 and g(-2) = 3 must be equal. This gives us:
(4a - 2b + c)/-3 = 3
Solving for b and c in terms of a, we get:
b = 3a/2 c = -9a/2
Plugging b = 3a/2 and c = -9a/2 into b + c = -1/2, we get:
3a/2 - 9a/2 = -1/2
This gives us a = -1/12.
Plugging a = -1/12 into b = 3a/2, we get:
b = 3(-1/12)/2 = -1/8
Plugging a = -1/12 and b = -1/8 into g(1) = b + c, we get:
g(1) = (-1/12) + (-1/8) = -7/24
Therefore, the point of intersection of the graphs of f(x) and g(x) that does not lie on the line x = -2 is (1, -7/24).
