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Is -2 a zero of the function ? P(x)=x^3-x^2-4x+14

If -2 is a zero then P(-2)=0

lets see if it works

$$P(-2)=(-2)^3-(-2)^2-4*-2+14=-8-4+8+14=10 \ne0$$

SO  -2 is not a zero.

EXTRA INFO

this means that (x+2)  IS NOT a factor of  P(x)

$$\\1.2=4.8t-1/2*9.81*t*t\\
1.2=4.8t-4.905t^2\\
4.905t^2-4.8t+1.2=0\\$$

$${\mathtt{4.905}}{\mathtt{\,\times\,}}{{\mathtt{t}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{4.8}}{\mathtt{\,\times\,}}{\mathtt{t}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1.2}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = {\mathtt{\,-\,}}{\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{35}}}}{\mathtt{\,\times\,}}{i}{\mathtt{\,-\,}}{\mathtt{160}}\right)}{{\mathtt{327}}}}\\
{\mathtt{t}} = {\frac{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{35}}}}{\mathtt{\,\times\,}}{i}{\mathtt{\,\small\textbf+\,}}{\mathtt{160}}\right)}{{\mathtt{327}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{t}} = {\mathtt{\,-\,}}\left({\mathtt{\,-\,}}{\frac{{\mathtt{160}}}{{\mathtt{327}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.072\: \!367\: \!948\: \!417\: \!379\: \!7}}{i}\right)\\
{\mathtt{t}} = {\frac{{\mathtt{160}}}{{\mathtt{327}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.072\: \!367\: \!948\: \!417\: \!379\: \!7}}{i}\\
\end{array} \right\}$$

There are 2 complex roots BUT NO REAL ROOTS

Thanks DevSeth, better late than never.   

A little bit of history.   

During his life Alfred Nobel was best known for inventing dynamite.  He wanted to be remembered for a less destructive accomplishment so upon his death in 1872 he left a trust to fund the awards of excellence that became known as the Nobel prizes.

Well Alan, I shall, give you 3 points for your first answer then - otherwise you would be getting cheated!  

Binary sufexes are (should be) used in these calculations

$${\frac{\left({\mathtt{1.5}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{40}}}\right)}{\left({\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{20}}}\right)}} = {\mathtt{524\,288}}$$

The following should help:

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The following graph should help you with question 26:

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Thank you anon for drawing our attention to this wonderful accolade that that has been recently given to this remarkable young woman.  

3x-3^4= x     subtract x from both sides

2x - 3^4 = 0   simplify

2x - 81 = 0      add 81 to both sides

2x = 81         divide both sides by -2

x = 81/2

Mmmmm...let's see what the Magic 8 Ball says..........

Oops......sorry.......wrong Magic 8 Ball !!!!

1.5 terabytes = 1.5 x 10¹² bytes

3 megabytes = 3 x 10⁶ bytes

So....... (1.5 x 10¹² ) / (3 x 10⁶ )  = about 500,000 songs

A terabyte has 10^12 bytes.

A megabyte has 10^6 bytes.

(1.5 x 10^12) ÷ (3 x 10^6)  =  (1.5 ÷ 3) x (10^12 ÷ 10^6)  =  (0.5) x (10^6)  =  5 x 10^5

Depends what you mean

(2,30) cannot be simplified  but

(12/2, -3/15) can be simplified to  (6,-1/5)

maybe they mean something like this

$$f(x)=-3(x)+5\\\\
\begin{tabular}{|c|c|c|c|c|}
\hline
$x$&1&2&3&4\\\hline
$f(x)$& \;&\; & \;& \;&\hline
\end{tabular}$$

This means

f(1)=-3*1+5=-3+5=2

so you put 2 in the box under the 1

Now you do the same with the other numbers.     

this is the second time you posted this question - I know because I just answered it.  

Please do not repost until the original question goes to the second page.  

Even then it would be polite for you to say that you are reposting.  

-2(x+4)>3x+17

first expand the brackets.

Now do it just the same as any other equation.

BUT REMEMBER

If you multiply OR divide be a negative number then you have to SWAP the sign (< or >) around.

and

I you swap the sides  you also have to SWAP the (< or >) sign around.

Now you try to do it and we can check your working and your answer.   

there is an invisable multiply sign between the 2000 and the bracket.

Is this why you could not do the question?

At least 11 means either 11 or 12:

Probability of 11:  12C11·(.80^11)·(.20^1)

Probability of 12:  12C12·(.80^12)·(.20^0)

Find the above two probabilities and add them.

y = x^2+8x+5

In the form y = ax^2 + bx + c, the x coordinate of the vertex is given by x = -b/2a

So here, a = 1 and b = 8

So  x = -8/2(1) = -4

And to find the y coordinate of the vertex, we just put the value for x back into the function.....so we have (-4)^2 + 8(-4) + 5 = 16 - 32 + 5 = -16 + 5 = -11

So the vertex is (-4, -11).....

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To answer the other two questions

x^2 + 18x + _____

Just take 1/2 of the coefficient on the x variable and square the resulting value.  Thus (1/2)18 = 9.....and 9^2 = 81. Thus, 81  is the number needed to complete the square (ensure a "perfect square trinomial)

For the second one, we have (1/2)(-5) = (-5/2)   and (-5/2)^2  = 25/4

x could be  or  6/3   or  11-9   etc  

you can think of more yourself.    

That is just another mystery to add to all the others that life offers.