Yes, that many Newtons.
$${\mathtt{45}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{35}}^\circ\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{9.8}} = {\mathtt{74.810\: \!939\: \!635\: \!795}}$$
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By the way, don't confuse the symbol N for the normal force with the symbol N meaning Newtons!
N (normal force) = 75 N (Newtons)