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How can I do that without guess and check?

Or is that the only way?

7L+11B

umm lets see

7,14,28,35,42,49,56,

can't make any of those with 7*8=56

49+11=60    So I can make 60                                   ANSWER IS NOT 60

42+11=53+11=64  can't make any using  7*6

35+11=46+11=57 can't make any using  7*5

28+11=39+11=50+11=61        SO 4*7+3*11=61     ANSWER IS NOT 61

14+4*11=58       so   2*7+4*11=58                         ANSWER IS NOT 58

7+5*11 = 62

So the answer is 59

Interesting...I didn't know the Carl Gauss part.

You didn't tell me that when I posted a similar question as anonymous, geno3141!

A series is called "arithmetic" if successive terms have a common difference.

This means, that when you subtract the first term from the second (2 - 1 = 1) and the second from the third

(3 - 2 = 1), the third from the fourth (4 - 3 = 1), etc., you always get the same answer. 

The sum of a finite arithmetic series is:  Sum = N(F + L) / 2

   N = number of terms = 100        F = first term = 1        L = last term = 100

Sum = 100(1 + 100)/2   --->   Sum = 100(101)/2   --->   Sum = 5050

This formula was created by mathematician Carl Gauss when he was in elementary school!

2 ft 9 3/32 x 5

2 ft 9 in =   2.75 ft     

So we have   (2.75 ft + 3/32 in) x 5  = (13.75 ft + 15/32 in)  = (13 ft, 9 + 15/32 in)

This is just pythagoras' theorem

the difference in the xes is   $$x_2-x_1$$

The difference in the y's is     $$y_2-y_1$$

You want the hyptotenuse (d)

$$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$

When I try graphing your function using my TI-83+, I keep getting an error ... I think because may calculator can't handle 365!

I believe that your formula is correct; it's just that the numbers are larger than your calculator's ability to handle them.

9 and 3/32 inches = (9+3/32)/12 feet

so if I understand you properly you want  5*(2+(9+3/32)/12 ) feet

you can do this on the site calc on the home page :)

Subtract 6 from 3Q784 = 3Q778    then Q must be 2

Proof 3642*9 + 6 = 32784

thank you!!!

Is there a way to solve without knowing 3^4=81?

Since  81  =  3^4

then:  1/81  =  3^-4

So:     3^x  =  3^-4     --->     x  =  -4

-1/2  =  sin( πx/11 )

Find the invsin of both sides:  invsin(-1/2)  =   πx/11

Multiply both sides by 11 and divide by π   --->   (11/π)invsin(-1/2)  =  x

(When you finish this, remember that there are two answers, one in Quadrant III and the other in Quadrant IV.)

Nope...just fine, Mathematician......

I assume this is (2 + 1/10) * (1 + 7/9)   ....if so, we have

21/10 * 16/9  =  ( swap denominators to make "canceling" easier )

21/9 * 16/10 =

7/3 * 8/5 =

56/15

Is my explanation correct? Or is it a little off?

10^(-2)   =   1 / (10^2)   =   1 / 100

$${{\mathtt{10}}}^{-{\mathtt{2}}} = {\frac{{\mathtt{1}}}{{\mathtt{100}}}} = {\mathtt{0.01}}$$

That's because you have to 1/10 * 1/10. When you do negative exponents, you are multiplying the number's recipricols. And 1/10 * 1/10 is the recipricol of ten multiplied by itself two times!

Yep! That's good.

When you wrote log4x, did you mean:  log (to the base 4) of x  or log (to the base to) of 4x?

First:  log (to the base 4) of x:  I'll skip the '4' when I type:

   (1/3)(logx + logz)  =  (1/3)(log(xy)      (because adding logs means that the numbers were multiplied)

    =  log[ (xy)^(1/3) ]       (because a multiplied goes into a log as an exponent) 

Second:  log (to the base 10 )

   (1/3)[log(4x) + log(4y)]  =  (1/3)[log(4x·4y)]  =  (1/3)[log(16xy)]  =  log[ (16xy)^(1/3) ]

So the answer's 2/3?

Am I understanding you?

Remainder of 6 then...24...right?

Oops, that wasn't you question; sorry!

First, subtract 6 from 3Q784 and then sum those digits to get a multiple of 9.

this person asked this question so long ago while others who asked after them got a response yet this person didn't what terrible service