All Answers 358514 Answers

Yes, anon is right LOL

But this thread might help you in the mean time.  :)

frequency = 2pi/3

$$\\x^2+y^2=5 \qquad(1a)\\
2y=x-3\qquad (2a)\rightarrow \;\;x=2y+3\qquad (2b)\\\\
sub\;2b\;into\;1a\\
\begin{array}{rll}
(2y+3)^2+y^2&=&5\\
4y^2+12y+9+y^2&=&5\\
5y^2+12y+4&=&0\\
5y^2+10y+2y+4&=&0\\
5y(y+2)+2(y+2)&=&0\\
(5y+2)(y+2)&=&0\\
\end{array}\\
y=-2/5\quad or\quad y=-2\\
When\;y=-2\;x=-4+3=-1\\
When\;y=-2/5\;x=-4/5+3=2\frac{1}{5}\\\\
$so the points of intersection are $ (2\frac{1}{5},\frac{-2}{5})\quad and \quad(-1,-2)$$

Here are the graphs.

Yes I thought that would be your problem.  

Your teacher wanted you to stress over it so that you are more likely to check next time.  

That is the mark of a good teacher :))  

Yes, Mathematician,  that is when you take the log of both sides.

$$\\log3^x=log(1/81)\\
xlog3=log(1/81)\\
x=log(1/81)/log(3)\\$$

$${\frac{{log}_{10}\left({\frac{{\mathtt{1}}}{{\mathtt{81}}}}\right)}{{log}_{10}\left({\mathtt{3}}\right)}} = -{\mathtt{3.999\: \!999\: \!999\: \!999\: \!999\: \!9}}$$

there is a little rounding error - its not a problem but it is more elegant to do it by hand if you can.

yes you did :) and yes you do need to do the distribution.    :)

It is 39 degrees celsius here today - that is about 100 degrees F       (Sydney)

I don't need sweat pants LOL.

$$\\-3x\le -4\\\\
$ divide both sides by -3 but remember that if you times or divide by a neg number you have to swap the sign around$\\\\
x\ge\frac{-4}{-3}\\\\
x\ge\frac{4}{3}\\$$

The exponent symbol is  ^      or   $$x^y$$

I am not sure what you mean but 

square root is a power of (1/2)

$$\\\sqrt[2]{x}=x^{1/2}\\\\
\sqrt[3]{x}=x^{1/3}\\\\
\sqrt[4]{x}=x^{1/4}\\\\
\sqrt[5]{x}=x^{1/5}\\\\
\sqrt[6]{x}=x^{1/6}\\\\
etc$$

A fith root is a power of 1/5

so you put this into the calc

64^(1/5)=

don't forget the brackets :))

Hi Melody,

$$\small{\text{
$
\begin{array}{|l|c|r|}
\hline
7^0...7^{21}&& 1...22 \\
\hline
7^0 & mod\ 23 & 1 \\
\hline
7^1 & mod\ 23 & 7 \\
\hline
7^2 & mod\ 23 & 3 \\
\hline
7^3 & mod\ 23 & 21 \\
\hline
7^4 & mod\ 23 & 9 \\
\hline
7^5 & mod\ 23 & 17 \\
\hline
7^6 & mod\ 23 & 4 \\
\hline
7^7 & mod\ 23 & 5 \\
\hline
7^8& mod\ 23 & 12 \\
\hline
7^9& mod\ 23 & 15 \\
\hline
7^{10}& mod\ 23 & 13 \\
\hline
7^{11}& mod\ 23 & 22 \\
\hline
7^{12}& mod\ 23 & 16 \\
\hline
7^{13}& mod\ 23 & 20 \\
\hline
7^{14}& mod\ 23 & 2 \\
\hline
7^{15}& mod\ 23 & 14 \\
\hline
7^{16}& mod\ 23 & 6 \\
\hline
7^{17}& mod\ 23 & 19 \\
\hline
7^{18}& mod\ 23 & 18 \\
\hline
7^{19}& mod\ 23 & 11 \\
\hline
7^{\textcolor[rgb]{1,0,0}{20}}& mod\ 23 & \textcolor[rgb]{1,0,0}{8} \\
\hline
7^{21}& mod\ 23 & 10 \\
\hline
\end{array}
$
}}$$

the power of button can look like a ^  that is what most people also use on the forum.

On some calcs it looks like       $$x^y$$

Thanks Chris - you are a sweetie         

Thanks Happy - I appreciate it.

Thanks Brittany  - And welcome to the forum :))

If you want to sue this calculator, you will have to take it to German court.

You should learn German, before you do this, but it might not be easy to do anyway, their laws are ambiguous on calculator suits.

Why do you want to sue this calculator to make a fraction? It really sounds like a division of justice.

I think you dropped a 'h' Cphill.       LOL

Maybe I should join this train - it seems everyone else has      LOL 

it is -1/12   

not -1 and a half  Brittany :))

yea I don't know either  LOL

there's that phi function again - it is sneaking in every where.

Thanks Heureka.  

How did you get that original 7^20 ?

im kinda a pro because i can talk REALLY fast so

😝😝😝😝😝😝😝😝

I can't even say that fast one time, jilllybean !!!!

You want e

On the site calc you can just enter e in the enter box.

On some calcs if you just want e you enter  e^1

I am not sure if that is any help   

brenda put her bitter butter in a battery to make her bitter butter better 5 times fast

OHMAGOSH, THANK YOU MELODY AND CPHILL!!!

I was plugging in 2500 for S, so it came out as

2500 = 10 (1-e^(5k))

250 = 1-e^(5k)

249 = -e^(5k)

Then ln( -249) = e^(5k), where I got stuck.

But now that it is 2.5, everything makes sense now!