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$$\sqrt{94}+20$$   

can't be simplified

$$\\ln \frac{(e^x)}{(1+e^x)}\\\\
ln (e^x)-ln(1+e^x)\\\\
x-ln(1+e^x)\\\\$$

Same form me CPHill..........gald to have you here........your like a walking shop of fun....whoever your around....they just start enjoying!

sin^2(-x)+cos^2(-x)

$$\boxed{
\begin{array}{ccc}
\sin(-x) &=& -\sin{x}\\
\cos(-x) &=& \cos(x)
\end{array}
}\\\\\\
\sin^2(-x)+\cos^2(-x)\\
=[-\sin(x)]^2+[cos(x)]^2\\
=\sin^2(x)+\cos^2(x)\\
=1$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\frac{{\mathtt{13}}}{{\mathtt{25}}}}\right)} = {\mathtt{0.009\: \!07}}$$

Is it possible that the lesson was regarding something else?

 For instance:

it is infinate so you cant just use 3.14 its easier and pretty accurate

its 4 

#just use a calculator

So what are the outputs for each one?

Both sin and cos range between 1 and -1. They start at different values.

The tangent ranges from zero to infinity. For all of the functions, you can get a good idea by rotating a radius (hypotenuse) of 1 counterclockwise around the origin (x and y axes).

What are the inputs of sine, cosine, and tangent?

More appropriate in a Physics class:

A decimal number is a number in the base ten numbering system which includes a decimal point. Digits to the left are whole numbers, digits to the right are multiples of 1/10 of the previous digit.

arcsin (1/2) means

$$Sin\theta=\frac{1}{2}$$

Recall that the sin function involves the ratio of the opposite side divided by the hypotenuse. So the opposite side is half of the hypotenuse. If you draw a 30-60-90 triangle with the hypotenuse equal to 1, you can determine that the side opposite the 30 degree angle is half as long.

Neopolitan

For the sine function,it is the ratio of the opposite side divided by the hypotenuse.

cosine is the adjacent side over the hypotenuse

and the tangent is the opposite side divided by the adjacent side.

It isn't really hard, the method of thinking is just new to you. Give it your best efforts, and don't give up. There is plenty og help available.

After you rearrange it to read

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{16}} = {\mathtt{0}}$$

You will see that it cannot easily be factored. You must use the Quadratic Formula.

www.purplemath.com/modules/quadform.htm

i answer the question with a question. what mindset do you have to be in to understand this? its like hyrogleiphics. 

This is just the equation of a line......x and y would take on infinite values

the answer is 2 : 15