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heureka i still dont understand the brackets part

why :x^3+6x^2+12x+16  -> (x+4)(x^2+2x+4)

Hallo sabi92,

I.  $$\small{\text{$
x^3+6x^2+12x+16:
$}}$$

  $$\small{\text{$
x = -4 \qquad \Rightarrow \qquad (-4)^3+6\cdot (-4)^2 + 12\cdot (-4) + 16
= -64 + 96 -48 + 16 = 0
$}}$$ 

II.   algebraic division:

$$\small{\text{$
x^3+6x^2+12x+16~~:~~(x+4) =x^2+2x+4
$}}$$

Circle area:   $$A = pi*r^2$$

Thank you Melody. I knew this was complicated and it will be a long time before I understand it.

I know that finding roots and findig zeros are the same thing. This becaue the y part is zero when the x is equal to something.  So the y can never be zero when the x part equal Pi. right?

Is the equation for a parabola a polynomial equation or is it something else? I think it is something else because it look like you can make one where it cross the x at Pi when y = 0. I will try to make one but I not sure I know how.

http://en.wikipedia.org/wiki/Golden_ratio

http://en.wikipedia.org/wiki/Golden_rectangle

 3.14

Hi Dragonlance,

It means that if you graph

$$y=a_1x^n+a_2x^{n-1}+a_3x^{n-2}+.................a_{n+1}$$

Where n is a positive integer and

where all the coefficients are rational numbers

and a_1 is not 0

That the graph can never cut the x axis at  $$\pi$$

(I don't know why not, but that is an explanation of what you just said)

Pi is a real number it is divisable by any other real number. You can not make it a fraction because it is irrational.

It is also a transcendental number that means is not a root of a non-zero polynomial equation with rational coefficients. I find that on the net but I dont know what it means.

Melody can you explaine it? Please.

Draw a right angled triangles with angles 20 and 70 degrees.  

Convince yourself that sin70 = cos 20

Now 

$$\\sin^2 20 + sin^2 70 \\\\
=sin^2 20 + cos^2 20 \\\\
=1\\\\\\
remember\; the\; identity\\\\
\boxed{sin^2 \theta + cos^2 \theta=1}$$

I'll take it from here MathsGod

64+6y= 2

You want the y by itself so to start with you will get 6y by itself.  

How can you get rid of the 64 from the left side?

Well you could take it away, but if you do it on the left you have to do it one the right as well.

64-64+6y=2-64

0+6y=-62

6y=-62

6*y=-62

now you need to get rid of  the *6  on the left side

The inverse of *6 is divide by 6 and divide is the same as a fraction.

So you have to divide by 6. But remember to do it on BOTH sides.  The equation must stay balanced

$$\\\frac{6y}{6}=\frac{-62}{6}\\\\
y=\frac{-62}{6}\\\\
y=\frac{-31}{3}\\\\
y=-10\frac{1}{3}\\\\$$

Just use the distance formula 3 times :)

That is great MathsGod1 but it is an improper fraction.

How about changing it to a mixed numeral ?

The acceleration is 2.5 meters per second²

It work like this

5m/s / 2s =

2.5m/(s*s) =

2.5m/s²

I know the answer is right but not to sure if the the way I do it is the best way.

I don't think that I am understanding the question.

Is each part  53000/2 ?

(4-x)=-1(-4+x)=-(x-4)

Is that your only problem here?

I assume you mean 15C8

put it into the web2 calc as nCr(15,8)

Why is it a golden rectangle?  What is so special about phi ?

antilog is just 10^(number)

$${sec}{\left({\mathtt{128}}\right)} = -{\mathtt{1.624\: \!269\: \!245\: \!481\: \!842\: \!5}}$$

that is 128 degrees

Thanks Chris, that is a really weird graph  :/

Pi is a non-terminating number that is used in finding the area of a circle, circumference of a circle, volume of a cylinder, etc. People normally show pi as 3.14.

-1.44321840075 I hope it helps!