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70 suit wearers - 25 unable to speak two languages - 20 with no beepers - 15 with no phone = 10 (minimum number of people who have all four)

I think it's density

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It true that DarkBlaze’s answer is not right. Civonamzuk is not right either.

The way this is written the temperatures are the same. Civonamzuk ask to compare - 40ºF, 233.16K , and - 40ºC and only the Kelvin temperature have decimal places in the question so if the temperature is within a half degree of C or F then it is considered the same temperature. The temperature would have to be written as -40.00F and -40.00C for it to matter about this small difference.

Civonamzuk you say it worth 2.5 pluses but you not even give one point to DarkBlaze.

Turn the percent into a decimal by moving the decimal point over two points to the left. 142.5% in decimal form is 1.425. Then multiply 20 by 1.425. The answer is 28.5.

28.5 is 142.5% of 20

(-7)2 + 26 / 5 -11 +13 / 2

Ok, because of the order of operations we must do the multiplication and division first.

-7*2=-14

26/5=5.2

13/2=6.5

So, -14+5.2-11+6.5

Now we can do the addition and subtraction.

-14+5.2=-8.8

-8.8-11=-19.8

-19.8+6.5=-13.3

The answer to your equation is -13.3 

0.6(x+5)+1.6(x-4)=

First, we simplify the equation by multiplying the 0.6 by the x and the 5 and also multiplying the 1.6 by the x and the 4 like this: 0.6x+3+1.6x-6.4=

Next, we further simplify by adding the like things together like this:2.2x-3.4=

Then we add 3.4 to both sides. This cancels out the -3.4 on the left side of the equals sign so that the equation reads: 2.2x=3.4

Then finally we divide both sides by 2.2 which cancels out the 2.2 on the left side of the equals sign. The equation ends up looking like this: x=1.55

Just plug the number in for the x in the original equation like this:0.6(1.55+5)+1.6(1.55-4)=

0.6(6.55)+1.6(-2.45)=

3.927-3.927=0

So, the answer is either x=1.55 or 3.927-3.927=0 

The answer is 100

I assume this is :  3b/(b+2) and 12/(b+2)  =  [ 3b + 12 ]  / [b + 2 ]  =  3[b + 4] / [b + 2 ]

25 feet  = 300 inches.....  and the slope is given by :

sin^-1 (25/300) = about 4.78°

2+6x-x^2   = 0     multiply through by -1 and rearrange

x^2 - 6x  - 2   = 0     this will not factor.......using the on-site solver (and the quadratic formula), we have...

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{3}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{11}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{11}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{0.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
{\mathtt{x}} = {\mathtt{6.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
\end{array} \right\}$$

yes, you can find energy with the information you are given.

the formula is Energy = Mass * the speed of light squared.

given the speed of light and the mass, which you have as 1,230,000 g and 299,792,458 m/s all you have to do is PEMDAS to find the missing component of the equation.

using PEMDAS, the E is exponent, and M is multiplication. Therefore, you must first square the speed of light before multiplying it by your mass.

Energy = 1,230,000 g (Mass, m) * 299,792,458² (Speed of Light, c)

E= 1,230,000 *89,875,517,873,681,764

E= 110,546,886,984,628,569,720,000

Hope this helps!

@DarkBlaze:/ You're half right;   - 40ºF = - 40ºC , but  273.16K  is slightly higher  (+ 0.01) then these two.  

To perform the operation, simply multiply 9087 by 0.59.

-40ºF and -40ºC are the same.

Converting Kelvin to celsius would be k-273, in which k is temperature in kelvin.

233.16-273=-40.16ºC

233.16K is the lowest temperature.

Hi Melody, :)

My End of Year assessment is in 2 days.

These are the topics I've studied since September

1. Place value and powers of 10

• Write digits in numbers and words
• Multiply and divide by 10, 100 ,1000
• Ordering positive, negative and decimal numbers on a number line

2. Rounding and estimation

• Rounding to the nearest whole number, 10, 100 and 1000
• Approximate answers to calculations by providing correct estimates

3. Adding and subtracting decimals

4. Mental calculations

• Know up to 12 x 12 times table
• Use BIDMAS/PEDMAS Correctly

5. Written calculations of positive and whole numbers

• Multiply and divide positive whole numbers

6. Factors, multiples and primes

• List factors of a given number
• Find the HCF and LCM of two numbers
• Understand what we mean by a prime number and identify all prime numbers between 1 and 10

7. Proportional reasoning

• Spot the difference between direct and inverse proportion
• Find missing quantities using direct and inverse proportion

8. More calculations

• And and subtract negative number
• Multiply and divide negative numbers
• Add and subtact decimal
• Multiply and divide decimal

9. Introduction to algebra

• Add, subtract, multiply and divide algebraic terms
• Expand brackets in algebra
• Substitution

10. Solving Equations

• Solve simple one step equation (EG) x+5=7
• Solve equation with two steps (EG) 2x-8=10
• Solve equations with unknowns on both sides
• Solving equation with brackets

11. Angles

• Draw and measure lines and angle
• Understand what we mean by paralles and perpendicualr lines
• Find missing angles in triangles and rectangles
• Use angle facrs to find algebra in a paralles lines 
• Calculate bearings and solve problems involving bearings

12. Proporties of shape

• Understand properties of triangle, quadrilateral and circle
• Use algebra to find missing lenghths
• Undestand properties of 3D shapes and draw plan, front and side elevation froma given 3D shape
• Find volumes and surface area of a shape

13. Fractions 

• Shade fractions and find equivalent fractions
• Ordering fractions 
• Find fractions of amounts
• Find a fraction of another fraction

14. Percentages

• Convert between fraction, decimals and percentages
• Make equivalent fractions with denominator over 100
• Find a percentage of a number
• Convert fractions and decimals greater than 100% to decimals.

Q1)

= 16cm^2

It's a square all sides are the same and finding the area times both sides.

Q2)

The area is 9^2 = 81

It's a square meaning all sides are the same.

So two SAME numbers that times together to make 81

9cm