All Answers 358087 Answers

Multiply the fraction 1/26 by 100 and add a % sign.

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There isn't one! 

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$$\small{\text{
Let $x$ and $y$ be integers satisfying $41x + 53y = 12$. Find the residue of $x$ modulo 53.
}}\\
\small{\text{
(Express your answer as an integer from 0 to 52.)
}}$$

$$\small{\text{
If $x=264$ and $y=-204$ then $41x + 53y = 12$.
}}\\
\small{\text{
The residue of $x\pmod{ 53 } = 52$.
}}$$

$$\small{
\begin{array}{llrl}
$(A)$ &\text{Find a number }$0\leq x< &14 &$that solves the congruence $9x \equiv 9 \pmod{14}$.\\
$(B)$&\text{Find a number }$0\leq x< &5 &$that solves the congruence $3x \equiv 4 \pmod{5}$.\\
$(C)$&\text{Find a number }$0\leq x< &1000&$that solves the congruence $999x \equiv 998 \pmod{1000}$.\\
$(D)$&\text{Find a number }$0\leq x< &21 &$that solves the congruence $4x \equiv 17 \pmod{21}$.
\end{array}
}$$

$$\left\{
\begin{array}{l}
$(A)$\\
$(B)$\\
$(C)$\\
$(D)$
\end{array}
\right\}=
\left\{
\begin{array}{lcr}
x&=&1\\
x&=&3\\
x&=&2\\
x&=&20
\end{array}
\right\}, \small{\text{ because }
\left\{
\begin{array}{lcr}
9\cdot 1 &\equiv& 9 \pmod{14}\\
3\cdot 3 &\equiv& 4 \pmod{5}\\
999\cdot 2 &\equiv& 998 \pmod{1000}\\
4\cdot 20 &\equiv& 17 \pmod{21}\\
\end{array}
\right\}$$

(A) Convince yourself that 50 is the inverse of 5 modulo 83, and that 12 is the inverse of 7 modulo 83. Find the inverse of 35 modulo 83. (Give your answer as a nonnegative integer that is less than 83.)

$$\small{\text{
The inverse of $35 \pmod{83} = \mathbf{ 19 }$, because $35 \cdot 19 \equiv 1 \pmod {83}$
}}$$

(b) Find the inverse of 49 modulo 83. (Give your answer as a nonnegative integer that is less than 83.)

$$\small{\text{
The inverse of $49 \pmod{83} = \mathbf{ 61 }$, because $49 \cdot 61 \equiv 1 \pmod {83}$
}}$$

What is the inverse of 100 modulo 10001? (Give your answer as a nonnegative integer that is less than 10001.)

$$\small{\text{
The inverse of $100 \pmod{10001} = \mathbf{ 9901 }$, because $100 \cdot 9901 \equiv 1 \pmod {10001}$
}}$$

It's already a fraction  !!!

We can reduce it to 9/17, though

2,8,25,50,75,100.....Magic number is 431

[(2 + 50)]8   + 75 / [√100- √25 ]  =

52 (8) + 75 / [10 - 5]  =

416 + 75/5  =

416 + 15   =

431

200(1+(.03/12))^(30(12))  = $491.37

A = 3.14 (6cm)^2   = 113.04 cm^2

Sorry! Yes, you must use all the numbers.

8 hours per day, and you have 31 days. 8 * 31 = 248

Your total is 248 hours

there is 4 possible answers to this question

it all depends on the month and the kind of year were in, either normal or leap

January=5,580 Pounds (31 days)

Febuary (Normal Year)=5,040 Pounds (28 Days)

Febuary (Leap Year)=5,220 Pounds (29 Days)

March=5,580 Pounds (31 Days)

April=5,400 Pounds (30 Days)

May=5,580 Pounds (31 Days)

June=5,400 Pounds (30 Days)

July=5,580 Pounds (31 Days)

August=5,580 Pounds (31 Days)

September=5,400 Pounds (30 Days)

October=5,580 Pounds (31 Days)

November=5,400 Pounds (30 Days)

December=5,580 Pounds (31 Days

How To Find The Possible Answers:

January, March, May, July, August, October, December (Each Have 31 Days): $${\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{31}} = {\mathtt{5\,580}}$$ Pounds

April, June, September, November (Each Have 30 Days): $${\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{30}} = {\mathtt{5\,400}}$$ Pounds

Febuary (Normal Year=28 Days): $${\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{28}} = {\mathtt{5\,040}}$$ Pounds

Febuary (Leap Year=29 Days): $${\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{29}} = {\mathtt{5\,220}}$$ Pounds

Q: If You Earn 180 Pounds A Day, How Many Do You Earn After 1 Month?

A: All Of The Above, The Month To Choose Is Your Choice

$${\mathtt{76\,578}}{\mathtt{\,\small\textbf+\,}}{\mathtt{38}} = {\mathtt{76\,616}}$$

$${\mathtt{3\,100}}{\mathtt{\,\times\,}}{\mathtt{0.291\: \!7}} = {\mathtt{904.27}}$$

the operation has been moved to the following page:

e= 2,71828 18284 59045 23536 02874 71352 66249 77572 47093 69995.... ;

8*2,71828 18284 59045 23536 02874 71352 66249 77572 47093 69995+18=39.746 (rounded to three decimals)

Actually, this can't be a right triangle because  4^2 + 5^2 ≠ 6^2

There is no diagram shown.....are you sure you have the correct info  ????

Solve : ((sqrt(2.9783)*2)-(2,3231^4))^2, in your head please.
Thats why.

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(x*x^2)   is the same as x^1 * x^2  = x^3  .....remember that we're using the rule that a^m * aⁿ = a ^m+n

There are three rectangular areas, each of which has the area of  (8 x 3)cm^2 = 24 cm^2....so these three areas have a total area of 72 cm^2

There are also three other "curved" areas. The angle opposite the "curved" part is 120°....then....these three areas would actually just comprise a circle with a radius of 3.......and the total area is just pi*(3)^2 =  9pi cm^2

So...the total area would be (72 + 9pi)cm^2 = about 100.274 cm^2

Notice that the general form of what we're given is :

x /[x + 11]    where x is the integer in the numerator.......look at this graph.....