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-9t?

kaip apskaicuti atstuma tarp kordinaciu plokstumos tasko A(- 15;8) iki ordinaciu asies??? abscisiu asies ir kordinaciu pradzios tasko? 

6r - 5t - 8r - 4t

OK.......what is the result of this  ???

6r - 8r       ????

And what is the result of this??

-5t - 4t    ????

Combine the results amd post your answer.......don't worry if you make a mistake....we'll work through it   !!!!

Oops, sorry....yep....1r....I'll make the correction....!!!!

Gal galite išversti gal kad į anglų kalbą

and did u mean 1r?

Thank u, sorry i'm posting so many questions, it's just i'm really bad at Algebra.

6q + 12r + 3q - 11r    again, since we are just adding and subtracting, we can rearrange the terms as:

6q + 3q + 12r - 11r  =

9q + 1r

No prob......!!!!

Omg thank u so much!

12b - 4c + 3b - 2c  =  combine like terms

12b + 3b - 4c - 2c  =

15b - 6c

I know right that's what the sites for

100000000000000000000000000000000000

Pretty sure

1 e9

I think?????????

Oh Well best luck

Thanks guest, that is a correct and a common way to do it.

I think of it slightly differently.

\(\frac{1}{x} = 0.016\\ \frac{1}{x} = \frac{0.016}{1}\\ Turn\; both\;sides\; upside\;down\\ \frac{x}{1} = \frac{1}{0.016}\\ x= \frac{1}{0.016}\\ \)

Then finish it on a calc :)

what is k+20=9k-4

Take k off both sides

THEN

add 4 to both sides.

Then divide both sides by the number in front of the k 

Then you will be finished :)

|x+2|=6

x+2=6    or     x+2=-6

there are 2 possibilities. 

1020/3[(5-1)^3-(-4)]-5^3

\(1020/3[(5-1)^3-(-4)]-5^3\\ =\frac{1020}{3}[(5-1)^3-(-4)]-5^3\\ =340[4^3-\;-4]-5^3\\ =340[64+4]-125\\ =340*68-125\\ =23120-125\\ =22995\)

10⁸ = 10^8 = 100 000 000

Actually I think that is pretty sound advice.  Thanks guest answerer :)

Go to this graphing calculator site and play with your ideas:

https://www.desmos.com/calculator

Let W be the width, then,

(W + 1) is the length.

But: W X (W+1)=342

W^2+W-342=0

W=-19 and W=18, so the width is:

W=18

L=18 + 1=19

Area=18 X 19=342m^2

WHEN IS IT LEGAL TO FLY THE AMERICAN FLAG AT HALF STAFF

225 = 300 - 75

225 = (300) x (225/300) = 300 (3/4)

\(\mbox{For a }n \times n \mbox{ matrix A, }Det[c A] = c^n Det[A], c \in \mathbb{R} \\ \mbox{so for }n=4, c=2, Det[2a]=2^4 Det[A] = 16 Det[A] = 16 \times \dfrac 1 2 = 8\)